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ycow [4]
3 years ago
8

If a baseball has a zero velocity at some instant, is the acceleration of the baseball necessarily zero at that time? Explain -

making sure to give an example of an object that has a zero velocity but non-zero acceleration.
Physics
1 answer:
ipn [44]3 years ago
3 0

Answer:

No, not necessarily

Explanation:

If an object is moving with an acceleration that causes its speed to be reduced, there will be a moment in which it reaches v = 0, but this doesn't necessarily mean that the acceleration isn't acting anymore. If the object continues its movement with the same acceleration, it's velocity will become negative.

An example of an object that has zero velocity but non-zero acceleration:

If you throw an object in the air with a certain velocity, it will move vertically, reducing its velocity in a 9,8 m/s^{2} rate (which is the acceleration caused by gravity). At a certain point, the object will reach its maximum height, and will start to fall. In the exact moment that it reaches the maximum height, before it starts falling, its velocity is zero, but gravity is still acting on the object (this is the reason why it starts falling instead of just being stopped at that point). Therefore, at that point, the object has zero velocity but an acceleration of 9,8 m/s^{2}.

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3 years ago
An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is giv
konstantin123 [22]

Answer:

8.91 %

Explanation:

Since v² = 2gy

By the relative error formula,

2Δv/v = Δg/g + Δy/y multiplying by 100%, we have

2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%

2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%

Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%

Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %

Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,

[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²

[Δg/g × 100 %]² = [2(3.69)]² + [5%]²

[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²

[Δg/g × 100 %]² = 54.4644 %² + 25%²

[Δg/g × 100 %]² = 79.4644 %²

taking square-root of both sides, we have

[Δg/g × 100 %] = 8.91 %

So, the percent uncertainty in the calculated value of g is 8.91 %

6 0
3 years ago
When a certain amount of current flows through a resistor, it uses 3.00 W of power. If the current doubles, how much power will
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7 0
3 years ago
Forces can act on an object in the same direction or in opposite. how does each situation affect the motion of the object?
Anon25 [30]



Hi pupil here's your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



Action and Reaction do not act on the same body !! If they acted on the same body, the resultant force will be zero and their could be never accelerated motion.

If both the forces acted on the same body, then if they are equal to opposite direction the object will remain stationary. If on of the forces is greater than other the object will move in the direction of greater force.

If both acted in the same direction there would be an accelrated motion.




⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅





Hope this helps . . . . .
5 0
3 years ago
Electrolytes serve several purposes in the body, including _________
vfiekz [6]

Answer:

Nerve and muscle function and fluid balance

Explanation:

:)

4 0
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