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Vinvika [58]
3 years ago
7

In which of these examples is the greatest movement occurring?

Physics
2 answers:
vlada-n [284]3 years ago
7 0
You need to provide a picture or tell us the examples... we can’t see what you see
Sloan [31]3 years ago
6 0

Answer:

The answer is C because it has the most movement going in one direction.

Explanation:

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6 latter word and it has a s and a I and it has mass (9.______________liquids, and gases all have mass.)
Firdavs [7]

Answer:

Solids

Explanation:

Solids, liquids, and gases all have mass.

7 0
2 years ago
What gravitational force does the earth exert on a person
lara [203]

The  gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.

<h3>What is the gravitational force of the earth on the person?</h3>

The gravitational force exerted by the earth on a person standing on the earth's surface is given below as follows:

  • F = \frac{Gm^{1}m^{2}}{r^{2}}

where

G = 6.67 * 10⁻¹¹

m¹ = 62 kg

m² = 5.97 * 10²⁷ kg

r = 6.4 * 10⁶ m

F = \frac{5.97*10^{24}*62*6.67*10^{-11}}{(6.4*10^{6}){2}} = 602.74\:N

Therefore, the gravitational force exerted by the earth on a person standing on the earth's surface is 602.74 N.

Learn more about gravitational force at: brainly.com/question/940770

#SPJ1

7 0
2 years ago
Bonsoir pouvez vous m'aider svp.<br>Mathématiques
LenaWriter [7]

bonsoir, je peux vous aider avec les maths laissez-moi comprendre merci

4 0
3 years ago
a tennis ball is thrown straight up with an initial velocity of 22.5 m/s how much total time is the ball in the air
lutik1710 [3]

Answer:

4.6s

Explanation:

v=u+at

0=22.5+(-9.8)t

-22.5=-9.8t

t=-22.5/-9.8

t=2.295 s

The total time will double

2.295×2=4.59s

=4.6s

6 0
3 years ago
A uniform 1500-kg beam, 20.0 m long, supports a 15,000-kg printing press
Ghella [55]

Answer:

\mathbf{F_1=4.41*10^4\ N}

\mathbf{F_2 = 1.176*10^5 \ N}

Explanation:

The missing image of the figure slide is attached in below.

However, from the model, it is obvious that it is in equilibrium.

As a result, the relation of the force and the torque is said to be zero.

i.e.

\sum F = 0 and \sum \tau = 0

From the image, expressing the forces through the y-axis, we have:

F_1+F_2 = W_B + W_P \\ \\ \implies 9.8(1500+15000) \\ \\ \implies  \mathtt{1.617\times 10^5 \ N}

Also, let the force F_1 be the pivot and computing the torque to determine F_2:

Then:

F_1(0)+F_2(20.0) = 10.0W_B + 15.0W_P

F_2 = \dfrac{((10*1500)+(15*15000))*9.8}{20.0}

F_2 = 117600 \ N

\mathbf{F_2 = 1.176*10^5 \ N}

For the force equation:

F_1+F_2=1.617*10^5 \ N;

where:

F_2 = 1.176*10^5 \ N

Then:

F_1+1.176*10^5 \ N=1.617*10^5 \ N

F_1=1.617*10^5 \ N-1.176*10^5 \ N

F_1=44100\ N

\mathbf{F_1=4.41*10^4\ N}

8 0
3 years ago
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