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aliina [53]
3 years ago
13

Another name for a "oxidation-reduction" reaction is

Chemistry
1 answer:
anzhelika [568]3 years ago
8 0
Redox (red for reduction and ox for oxidation)
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How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl
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Answer:

A) 8.00 mol NH₃

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Part B:

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4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

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6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

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