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Olenka [21]
3 years ago
13

A different group of students decided to do this experiment by

Physics
1 answer:
GaryK [48]3 years ago
8 0

Answer:

Using an object of less mass can reduce the energy lost due to friction.

Explanation:

let the mass of the object be M.

acceleration due to gravity be g, coefficient of kinetic friction between object and slider be \alpha  , angle between horizntal and slider be ∅ and distance slided by the object be d.

work done by friction of the ramp will be the energy lost by ramp due to friction.

work done = force×displacement

force = \alpha×M×g×cos∅

displacement= d

therefore work done =  \alpha×M×g×cos∅×d

therefore on decreasing the mass M we can see that work done by friction decreases so the energy lost due to friction also decreases.

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A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of
vladimir2022 [97]

For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice?  is mathematically given as

x = 9.93 g

<h3>What is the amount of water that freezes onto the ice?</h3>

Where

Energy received = energy given out

Generally, the amount of water is mathematically given as

(53)(0.5)(30) = (80)(x)

Therefore

x = (49)(0.5)(16)/(80)

x = 9.93 g

In conclusion, the mass of water

x = 9.93 g

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brainly.com/question/15959704

4 0
2 years ago
During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.
swat32

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

Charge Q= 330C

Current I= ??

The expression for the electric current is given as

Q= It

Substituting we have

330= I*57

I= 330/57

I=5.78 amps

Hence the current is 5.78amps

3 0
3 years ago
A cube made Of an unknown material has a height of 9 symeters the mass of this cube is 3645 g. calculate the density of this cub
kherson [118]

Answer: 5 \frac{g}{cm^{3}}

Explanation:

The density \rho of a material is given by:

\rho=\frac{m}{V} (1)

Where:

m=3645 g is the mass of the cube

V is the volume of the cube

Now, the volume of a cube is equal to the length L of its edge to the power of 3:

V=L^{3} (2)

If we know L=9 cm, the volume of this cube is:

V=(9 cm)^{3}=729 cm^{3} (3)

Substituting (3) in (1):

\rho=\frac{3645 g}{729 cm^{3}} (4)

\rho=5 \frac{g}{cm^{3}} This is the density of the cube

8 0
3 years ago
Time: distance: direction:velocity
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Do you want the formula?

7 0
3 years ago
What is 7.325 NS x 10 to the 549 power GS equal?
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Idrk sorry ___\........../.....
5 0
3 years ago
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