10.4 N
Given
m = 1.10 kg
θ = 15.0°
g = 9.81 m/s2
Solution
Fnet, y = ΣF y = Fn − Fg, y = 0
Fn = Fg, y = Fg
cosθ = mgcosθ
Fn = (1.10 kg)(9.81 m/s2
)(cos15.0°) = 10.4 N
Answer:
2600 m
Explanation:
A fathometer produces a sound wave and then detects the echo. It takes 3.5 seconds for the echo to reach the ship, so that means it takes half the time (1.75 seconds) to reach the ocean floor.
The speed of sound in seawater is approximately 1500 m/s, so the depth of the ocean at that point is:
d = 1500 m/s × 1.75 s
d = 2625 m
Rounding to two significant figures, the depth is approximately 2600 m.
F = M A
Force = (mass) x (acceleration)
= (1,650 kg) (4 m/s²) = 6,600 kg-m/s² = <em>6,600 Newtons</em>
<span>Convert 200 km to meters which equals 200000 meters. Then take 10m/s*200000meters which equals 2000000 seconds.
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Answer:
v = 54m/s
Explanation:

a = 7m/s²
u = 12m/s
t = 6s
7 = (v-12)/6
v - 12 = 42
v = 54m/s
(Correct me if i am wrong)