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3 years ago

How to calculate sound of an echo

Physics

1 answer:

bonufazy [111]3 years ago

5 0

by an echo meter

please flw me and thank my answers

#Genius kudi

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Suppose you apply a force of 75 N to a 25-kg object. What will the acceleration of the object b? (Remember a=F/m)

Vlada [557]

I would choose the option B.

F = ma

a = 75 / 25 = 3 m/s^2

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2 years ago

How can you use the movement of molecules to determine when a phase change has occurred?

baherus [9]

Answer:

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance. The example we will use here is ice melting into water.

Explanation:

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3 years ago

Read 2 more answers

A roller coaster is stationary at the top of a ramp.

Serjik [45]

Answer:

Explanation:

The roller coaster is stationary so the kinetic energy would be zero, but it is at the top of ramp so the potential energy would be high as its gravitational so it would have to be A

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3 years ago

Si se deja caer un carrito de una pista de coches sin friccion y su altura inicial es de 1.4 metros, cual es la velocidad maxima

Svet_ta [14]

Answer:

$5.241\ \text{m/s}$

Explanation:

m = Masa del coche

g = Aceleración debida a la gravedad = $9.81\ \text{m/s}^2$

h = Altura = $1.4\ \text{m}$

v = Velocidad del automóvil en la parte inferior de la pista

Aquí asumimos que el automóvil desciende verticalmente. La energía potencial del automóvil se completará convertida en energía cinética en la parte inferior de la pista ya que no hay pérdida de energía.

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.4}\\\Rightarrow v=5.241\ \text{m/s}$

La velocidad máxima que puede alcanzar el coche es $5.241\ \text{m/s}$ .

8 0

3 years ago

147.5 ml of ethyl alcohol (coefficient of volume expansion = 1120 x 10-6K-1) at a temperature of 273.1 K is measured into a 150.

marishachu [46]

Answer:

288.2 K

Explanation:

$\beta$ = Volumetric expansion coefficient = $1120\times 10^{-6}\ /K$

$T_i$ = Initial temperature = 273.1 K

$T_f$ = Final temperature

$v_0$ = Original volume = 150 mL

Change in volume is given by

$\Delta v=\beta v_0(T_f-T_i)\\\Rightarrow T_f=\frac{\Delta v}{\beta v_0}+T_i\\\Rightarrow T_f=\frac{150-147.5}{1120\times 10^{-6}\times 147.5}+273.1\\\Rightarrow T_f=288.2\ K$

The temperature of the ethyl alcohol should be 288.2 K to reach 150 mL

8 0

3 years ago

How to calculate sound of an echo ​

How to calculate sound of an echo