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Dmitriy789 [7]
2 years ago
5

How to calculate sound of an echo ​

Physics
1 answer:
bonufazy [111]2 years ago
5 0

by an echo meter

please flw me and thank my answers

#Genius kudi

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A proton that has a mass m and is moving at 270 m/s in the i hat direction undergoes a head-on elastic collision with a stationa
Nataly_w [17]

Answer:

V_p = 267.258 m/s

V_n = 38.375 m/s      

Explanation:

using the law of the conservation of the linear momentum:

P_i = P_f

where P_i is the inicial momemtum and P_f is the final momentum

the linear momentum is calculated by the next equation

P = MV

where M is the mass and V is the velocity.

so:

P_i = m(270 m/s)

P_f = mV_P + M_nV_n

where m is the mass of the proton and V_p is the velocity of the proton after the collision, M_n is the mass of the nucleus and V_n is the velocity of the nucleus after the collision.

therefore, we can formulate the following equation:

m(270 m/s) = mV_p + 14mV_n

then, m is cancelated and we have:

270 = V_p + 14V_n

This is a elastic collision, so the kinetic energy K is conservated. Then:

K_i = \frac{1}{2}MV^2 = \frac{1}{2}m(270)^2

and

Kf = \frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2

then,

\frac{1}{2}m(270)^2 =  \frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2

here we can cancel the m and get:

\frac{1}{2}(270)^2 =  \frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2

now, we have two equations and two incognites:

270 = V_p + 14V_n  (eq. 1)

\frac{1}{2}(270)^2 =  \frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2

in the second equation, we have:

36450 =  \frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2  (eq. 2)

from this last equation we solve for V_n as:

V_n = \sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }

and replace in the other equation as:

270 = V_p + 14\sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }

so,

V_p = -267.258 m/s

Vp is negative because the proton go in the -i hat direction.

Finally, replacing this value on eq. 1 we get:

V_n = \frac{270+267.258}{14}

V_n = 38.375 m/s  

3 0
3 years ago
70 POINTS AND BRAINLIEST PLEASE HELP!!!The Moon orbits Earth. This orbit causes the Moon to look different over the course of ab
Rudik [331]

Answer:

It always acurs after a 1st quarter

do you have photo?

Explanation:

8 0
3 years ago
What is one way to describe elements
Talja [164]

Answer:

They are the smallest pancise of any matere

4 0
3 years ago
A horse shoe magnet is placed on a mass balance such that a uniform magnetic field of magnitude B runs between it from North to
BARSIC [14]

Answer:

(a) Measured change in mass (Δm) = BVL/Rg

(b) Total measured mass M' = M - BVL/Rg

Explanation:

Current (I) across is coil is given by the formula;

I = V/R ------------------------1

The magnetic force is given by the formula;

Fb = B*I*L -------------------2

Putting equation 1 into equation 2, we have;

Fb = B*V*L/R -------------------3

Change in mass (Δm) is given as:

Δm = Fb/g -----------------------4

Putting equation 3 into equation 4, we have;

Δm = BVL/Rg

   Therefore,  change in mass (Δm) = BVL/Rg

2. Since B runs from North to South and current running from East to West, then the magnetic force is directed upward.

Therefore,

Total measure mass M' = M - BVL/Rg

4 0
3 years ago
What is an equilibrant
professor190 [17]
The question seems to be what is an equilibrant force.

The answer is "an added force that produces equilibrium.

Here you have more insight:

<span>an object that has no net force acting on it? This object indeed is in equilibrium but the object is not the equilibran force.

the reaction force in an action-reaction pair of forces?

the reaction force is not an equilibrant force. The reaction force exists always but equilibrium is only possible if the net force is cero.

an added force that produces equilibrium? this is the right  answer.</span>
5 0
3 years ago
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