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nikklg [1K]
3 years ago
11

Identify the neutral element represented by this excited-state electron configuration, then write the ground-state electron conf

iguration for that element.
Excited state: 1s2 2s2 2p3 3s1
Chemistry
1 answer:
Kipish [7]3 years ago
4 0

Answer:

The element is oxygen.

1s² 2s² 2p⁴

Explanation:

Let's consider the electron configuration of the excited state.

1s² 2s² 2p³ 3s¹

According to the Aufbau principle, the electron in 3s should occupy the shell with lower energy. The ground-state electron configuration is:

1s² 2s² 2p⁴

The differential electron is in the level 2. Then, the element is in the period 2.

The electrons in the last level are 2 + 4 = 6. Then, the element is in the group VIA or 16.

The element is oxygen.

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Equation is balanced already
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Molar Mass (C₄H₁₀): 58.124 g/mol

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2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O

 48 g O₂             1 mole             2 moles C₄H₁₀            58.124 g
---------------  x  -----------------  x  -------------------------- x  ------------------  =  
                         31.996 g              13 moles O₂               1 mole

=  13 g C₄H₁₀

 48 g O₂             1 mole               8 moles CO₂            44.007 g
---------------  x  -----------------  x  -------------------------- x  ------------------  =  
                         31.996 g              13 moles O₂               1 mole

=  41 g CO₂

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