Answer:the human retina can only detect incident light that falls in waves 400 to 720 nano-meters long so we cant see microwave or ultraviolet wavelengths. this also applies to infrared lights which has wavelengths longer than visible and shorter than microwaves thus being invisible to the human eye
Explanation:
Answer: <u><em>D a source of electricity</em></u>
Explanation: I have done that question please tell me if it is correct
1) 260 km/h
Let's use the following convention:
positive x-direction = east
positive y-direction = north
Here we have to find the north component of the velocity's airplane, which means we have to find its y-component.
We can use the formula:
![v_y = v sin \theta](https://tex.z-dn.net/?f=v_y%20%3D%20v%20sin%20%5Ctheta)
where
v = 750 km/h is the magnitude of the plane's velocity
is the angle between the direction of the plane and the positive x-axis
Substituting,
![v_y = (750)(sin 20)=256.5 km/h \sim 260 km/h](https://tex.z-dn.net/?f=v_y%20%3D%20%28750%29%28sin%2020%29%3D256.5%20km%2Fh%20%5Csim%20260%20km%2Fh)
2)
north of east
In order to find the direction of flight, we have to consider that the vector representing the displacement of the plane is the hypothenuse of a right triangle, of which the displacements along the east and north direction are the sides.
Therefore, we have
is the displacement towards east
is the displacement towards north
Therefore, the angle that gives the direction is given by
![tan \theta = \frac{v_y}{v_x}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7Bv_y%7D%7Bv_x%7D)
And substituting,
![\theta =tan^{-1}( \frac{100}{200})=24^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3Dtan%5E%7B-1%7D%28%20%5Cfrac%7B100%7D%7B200%7D%29%3D24%5E%7B%5Ccirc%7D)
and this angle is measured north of east.
Answer:
177 coulomb
Explanation:
Given data
I=2.95A
T=60
The relationship between current I and quantity of charge Q.
Q=IT
Substitute
Q=2.95*60
Q=177 coulomb
It’s the second one refracted rays