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svlad2 [7]
3 years ago
15

The reaction of 15 moles carbon with 30 moles O2 will

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer:

15 moles.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

C+O_2\rightarrow CO_2

Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:

n_{CO_2}=15molC*\frac{1molCO_2}{1molC} \\\\n_{CO_2}=15molCO_2

Best regards.

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Read 2 more answers
Which statements are true concerning elements in the same group of the periodic table? Select all that apply.
Tatiana [17]

The statements A and F are true concerning elements in the same group of the periodic table.  

To select all that apply, we need to evaluate each statement.

A. They have similar periodic properties.  

This statement is true. All the elements in the same group will have similar chemical and physical properties due to the electron configuration of their outer shell. For example, the alkali metals group (Li, Na, K, Rb, Cs, and Fr), has a valence electron configuration of s¹ (in the outer shell), which gives them the tendency to react vigorously with water, as well as other properties.      

B. They are all metals or nonmetals, but not both.

This is false. If we take a look at the p-block of the periodic table, we can see that the <u>groups</u> in this block are conformed by nonmetals, metals, and metalloids. For example, the icosagens group is formed by metalloids (B) and metals (Al, Ga, In, Tl).          

 

C. They are either all solids or all liquids or all gases.

This is false. In some groups, all the elements are solids (alkaline earth metals) or gases (group of noble gases), but in others, the groups are conformed by gases with solids (pnictogens group) or by gases with liquids (halogens group).  

   

D. They have the same number of shells of electrons.

This is false. In a group, the number of shells <u>increases from top to bottom</u> in the periodic table. For example, the electron configuration of the elements in the alkali metals is:        

  • H: 1s¹      
  • Li: [He]2s¹
  • Na: [Ne]3s¹
  • K: [Ar]4s¹
  • Rb: [Kr]5s¹
  • Cs:  [Xe]6s¹
  • Fr: [Rn]7s¹

We can see that hydrogen has 1 shell and Cs has 6 shells.  

E. They have the same number of inner core electrons.

This is false. As we said at point D, the number of shells increases from top to bottom in a group, so the number of inner core electrons also increases in this order. For example, in the alkaline earth metals group, the electron configuration of the elements is:  

  • Be: [He]2s²
  • Mg: [Ne]3s²
  • Ca: [Ar]4s²
  • Sr: [Kr]5s²
  • Ba: [Xe]6s²
  • Ra: [Rn]7s²

As we can see, the number of inner shells increases from Be ([He]) to Ra ([Rn]).    

F. They have the same outer shell electron configuration.

This is true. As we said at point A, the elements in the same group will have the same electron configuration of the outer shell (valence electron configuration). At points D and E, we can see that the valence electron configuration is the same for all the elements in the groups.    

Therefore, statements A and F are true.      

You can find more about the periodic table here: brainly.com/question/4287157?referrer=searchResults

I hope it helps you!    

           

6 0
3 years ago
what is the molarity of a solution prepared dissolving 317 g of CaCl2 into enough water to make 2.50 L of solution?
Minchanka [31]

Answer:

1.14 M

Explanation:

Step 1: Calculate the moles corresponding to 317 g of calcium chloride (solute)

The molar mass of calcium chloride is 110.98 g/mol.

317 g CaCl₂ × 1 mol CaCl₂/110.98 g CaCl₂ = 2.86 mol CaCl₂

Step 2: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = moles of solute / liters of solution

M = 2.86 mol / 2.50 L = 1.14 mol/L = 1.14 M

4 0
3 years ago
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