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likoan [24]
3 years ago
8

A pool ball hits a second pool ball with equal mass. The first pool ball comes to a complete stop, while the second pool ball ro

lls away. How does the velocity of the second pool ball compare to the original velocity of the first pool ball? A. The second pool ball's velocity will be less than the first pool ball's. B. The second pool ball's velocity will be the same as the first pool ball's. C. The second pool ball's velocity will be greater than the first pool ball's. D. The second pool ball's velocity will be exactly double the first pool ball's.
Physics
1 answer:
zubka84 [21]3 years ago
3 0

A pool ball hits a second pool ball with equal mass. The first pool ball comes to a complete stop, while the second pool ball rolls away.

The second pool ball's velocity will be the same as the first pool ball's velocity was.<em> (B)</em>  

And that's literally 'velocity', not just speed.  The second ball must take off from the collision with the same speed AND in the same direction as the first ball.  

That's the only way that momentum can be conserved !

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Why do things become hot or cold?<br> Relate to Thermal Energy and The Law of Conservation of Energy
Mekhanik [1.2K]

<u>Answer:</u>

Things become hot and cold because of the transfer of energy.

<u>Explanation:</u>

The energy possessed by an object or system is called thermal energy and heat is the flow of this energy. While the law of conversation of energy states that energy is not destroyed or created, it just transfers from one object to another.  

When a hot object is placed in normal conditions, it transfers heat to the environment until both are at the same temperature and heat transfers from the environment to the cold objects placed in normal conditions.

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A chart labeled table A : effect of height on temperature with initial temperature as 25 degrees Celsius, mass w is 1.0 kilogram
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Answer:

100m: 4.9 kJ

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Explanation:

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3 years ago
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At which of the following temperature and pressure levels would a gas be most likely to follow the ideal gas law? A. 0 K and 100
bulgar [2K]
The Ideal Gas Law makes a few assumptions from the Kinetic-Molecular Theory. These assumptions make our work much easier but aren't true under all conditions. The assumptions are,

1) Particles of a gas have virtually no volume and are like single points.
2) Particles exhibit no attractions or repulsions between them.
3) Particles are in continuous, random motion.
4) Collisions between particles are elastic, meaning basically that when they collide, they don't lose any energy.
5) The average kinetic energy is the same for all gasses at a given temperature, regardless of the identity of the gas.

It's generally true that gasses are mostly empty space and their particles occupy very little volume. Gasses are usually far enough apart that they exhibit very little attractive or repulsive forces. When energetic, the gas particles are also in fairly continuous motion, and without other forces, the motion is basically random. Collisions absorb very little energy, and the average KE is pretty close.

Most of these assumptions are dependent on having gas particles very spread apart. When is that true? Think about the other gas laws to remember what properties are related to volume.

A gas with a low pressure and a high temperature will be spread out and therefore exhibit ideal properties.

So, in analyzing the four choices given, we look for low P and high T.

A is at absolute zero, which is pretty much impossible, and definitely does not describe a gas. We rule this out immediately.

B and D are at the same temperature (273 K, or 0 °C), but C is at 100 K, or -173 K. This is very cold, so we rule that out.

We move on to comparing the pressures of B and D. Remember, a low pressure means the particles are more spread out. B has P = 1 Pa, but D has 100 kPa. We need the same units to confirm. Based on our metric prefixes, we know that kPa is kilopascals, and is thus 1000 pascals. So, the pressure of D is five orders of magnitude greater! Thus, the answer is B.
6 0
4 years ago
If v = 5.00 meters/second and makes an angle of 60° with the negative direction of the y–axis, calculate all possible values of
Goshia [24]
Vx = + 4.33 m/s. Hope this helps
8 0
3 years ago
If a force of 2n does work at the rate of -2sqrt2 w on an object moving iwth a speed of 2m/s the ale between the fore and teh ve
GrogVix [38]

Answer:

The value of the angle theta = 135degree, which is option c.

Explanation :

These are the options given in the question

a) 45 degrees

b)120 degrees

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d)150 degrees

e) it is impossible to deliver a negative power.

The concept of work done on an object is applied here.

work = Fd

F = ma

work = mad

Work is a form of energy transferred by an object after the application of a force that act on the object. A step by step explanation is as attached below.

6 0
3 years ago
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