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Elenna [48]
3 years ago
15

A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with specific gravity of 1.7. The ma

nometer reading is 320 mm. What is the pressure difference
Engineering
2 answers:
ipn [44]3 years ago
5 0

Answer :pressure difference is Δp=5,32pa

Explanation : the expression for pressure difference at the top of the manometer can be given as

P1-P2=Rg(ρm-ρs)...... 1

For gases, ρs is negligibly small when compared to ρm . So substitute zero for in equation (1) and re-write the final expression

Δp=Rg(ρm)

Here,

Δp is the differential pressure applied to manometer in Pa or psi

R is the difference in the levels of the two interfaces in meters 320mm

To metre =0.320m

g is the acceleration of gravity

ρm is the manometer liquid density in 9.81m/s²

Specific gravity(sg) of liquid 1.7

Density of water is 997 kg/m³

Sg=density of substance/density of water

1.7=density of substance/997

Density of substance=1.7*997

=1694.9kg/m³

Hence solving for pressure difference

Δp=Rg(ρm)

=0.320*9.81*1694.9

Δp=5,32pa

MArishka [77]3 years ago
3 0

Answer:

5320.6 Pascal

Explanation:

Manometer is a pressure measuring device use to measure gas pressure .

Pressure difference in Manometer is a function of density,gravity and the height difference of the liquid.

Pressure difference = density x acceleration due to gravity x difference in height of liquid

Density of liquid = specific gravity of object x density of water.

Density of water = 997 kg/m^3

Specific gravity of liquid = 1.7

Density of liquid = 997 x 1.7 =1694.9kg/m^3

g= 9.81 m/s^2

h =320mm = 0.320m

Pressure difference = 1694.9 x 9.81 x 0.320 = 5320.6 Pascal

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Air is saturated with water vapor at 35.0 oC and a total pressure of 1.50 atmospheres. If the molar flow rate of the dry air in
Marizza181 [45]

Answer:

11.541 mol/min

Explanation:

temperature = 35°C

Total pressure = 1.5 * 1.013 * 10^5 = 151.95 kPa

note : partial pressure of water in mixture = saturation pressure of water at T = 35°c )

from steam table it is = 5.6291 Kpa

calculate the mole fraction of H_{2}o ( YH_{2}o )

= 5.6291 / 151.95

= 0.03704

calculate the mole fraction of air ( Yair )

 = 1 - mole fraction of water

= 1 - 0.03704 = 0.9629

Now to determine the molar flow rate of water vapor in the stream

lets assume N = Total molar flow rate

NH_{2}o = molar flow rate of water

Nair = molar  flow rate of air = 300 moles /min

note : Yair * n = Nair

therefore n = 300 / 0.9629 = 311.541  moles /min

Molar flowrate of water

=  n -  Nair

= 311.541 - 300 = 11.541 mol/min

4 0
3 years ago
A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid.
Trava [24]

Answer:

a. Heat removal rate will increase

b. Heat removal rate will decrease

Explanation:

Given that

One end of rod is connected to the furnace and rod is long.So this rod can be treated as infinite long fin.

We know that heat transfer in fin given as follows

Q_{fin}=\sqrt{hPKA}\ \Delta T

We know that area

A=\dfrac{\pi}{4}d^2

Now when diameter will triples then :

A_f=\dfrac{\pi}{4}{\left (3d \right )}^2

A_f=9A

Q'_{fin}=\sqrt{9hPKA}\ \Delta T

Q'_{fin}=3\sqrt{hPKA}\ \Delta T

Q'_{fin}=3Q

So the new heat transfer will increase by 3 times.

Now when copper rod will replace by aluminium rod :

As we know that thermal conductivity(K) of Aluminium is low as compare to Copper .It means that heat transfer will decreases.

3 0
2 years ago
when electric power is transmitted over long distance, line losses can be reduced by generating AC rather than DC voltage and by
Tanya [424]

When electric power is transferred over a long distance then, line loss can be reduced by high voltage and low current. Thus, option A is correct.

<h3>What is electric power?</h3>

The complete question is attached to the image below.

The electric circuit transfers the electric current then it is called electric power. The loss in the line over a larger distance is reduced by transferring AC instead of DC voltage.

The AC transmitted is of high voltage, and the power is low. The equation for current is given,

P = VI

The increase in the voltage causes the decrease in the current and in turn the resistance also reduces resulting in the loss of the power of the circuit to decrease.

Therefore, the loss is reduced by transferring high voltage and, low current AC.

Learn more about high volatge AC here:

brainly.com/question/18069892

#SPJ1

3 0
1 year ago
Work done by a system during a process can be considered as a property of the system. a)True b) False
SVEN [57.7K]

Answer:

b) False

Explanation:

Work done by a system is not a property because it doesn't define the system's state. Work is mechanical energy exchanged across the system's boundaries.

6 0
3 years ago
A single-lane bridge connects the two Vermont villages of North Tunbridge and South Tunbridge. Farmers in the two villages use t
Naddika [18.5K]

Answer:

Check the explanation

Explanation:

Main1.java

import java.lang.InterruptedException;

import java.lang.Thread;

import java.util.Random;

public class Main {

final private static int FARMERS = 10;

public static void main(String[] args) {

Bridge bridge = new Bridge();

Random r = new Random();

System.out.println("Running with " + FARMERS + " farmers...");

// Enter a bunch of farmers from different directions.

for (int i = 0; i < FARMERS; i++) {

Farmer farmer;

if (r.nextBoolean()) {

farmer = new SouthBoundFarmer(bridge);

} else {

farmer = new NorthBoundFarmer(bridge);

}

cross(farmer);

}

}

private static void cross(Farmer f) {

new Thread(f).start();

}

}

SouthBoundFarmer.java

public class SouthBoundFarmer extends Farmer {

public SouthBoundFarmer(Bridge b) {

super(b);

this.name = "South";

}

}

Farmer.java

import java.lang.InterruptedException;

import java.util.Random;

public class Farmer implements Runnable {

private Bridge bridge;

private Random random;

protected String name;

public Farmer(Bridge b) {

this.bridge = b;

this.random = new Random();

}

public void crossBridge(Bridge bridge) {

System.out.println("[" + this.name + "] Waiting to enter bridge...");

try {

bridge.enter();

System.out.println("[" + this.name + "] Entering bridge...");

// Crossing bridge...some farmers are fast, others are slow :P

Thread.sleep(1000 + random.nextInt(9000));

System.out.println("[" + this.name + "] Leaving bridge...");

} catch (InterruptedException e) {

System.out.println("...Interrupted!");

} finally {

bridge.leave();

}

}

public void run() {

this.crossBridge(this.bridge);

}

}

Bridge.java

import java.lang.InterruptedException;

import java.util.concurrent.Semaphore;

public class Bridge {

private Semaphore lock;

public Bridge() {

this.lock = new Semaphore(1);

}

public void enter() throws InterruptedException {

this.lock.acquire();

}

public void leave() {

this.lock.release();

}

}

NorthBoundFarmer.java

public class NorthBoundFarmer extends Farmer {

public NorthBoundFarmer(Bridge b) {

super(b);

this.name = "North";

}

}

KINDLY CHECK THE OUTPUT BELOW :

4 0
3 years ago
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