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mars1129 [50]
3 years ago
13

A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne

gligible, what force must the rope provide to pull a 500 N person up the hill at a constant rate?
Physics
1 answer:
Charra [1.4K]3 years ago
5 0

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

W_x = 500 cos37

W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

F = W_y = 500 sin37

F = 300 N

so it apply 300 N force along the inclined plane

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1. Determine the image distance in each of the following.
miskamm [114]

It is given that for the convex lens,

Case 1.

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v

1

−

u

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=

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−

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1

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−

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The image in formed in this case at a distance of 24.3cm in left of lens.

Case 2.

A point source is placed in between the lens and the mirror at a distance of 40 cm from the lens i.e. the source is placed at the focus of mirror, then the rays after reflection becomes parallel for the lens such that

u=∞

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Now, using mirror’s formula

v

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+

u

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=

f

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v

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6 0
3 years ago
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Vanyuwa [196]

there will no resultant force

Explanation:

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5 newton's ---------> <--------- 5 newton's

then both forces will cancel each other out as a result there is no resultant force and the newton's laws states that if there is no resultant the object will continue in its state of rest (remains there) or it will in continue in its uniform motion in a straight line.

I hope you understand,

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