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mars1129 [50]
4 years ago
13

A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne

gligible, what force must the rope provide to pull a 500 N person up the hill at a constant rate?
Physics
1 answer:
Charra [1.4K]4 years ago
5 0

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

W_x = 500 cos37

W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

F = W_y = 500 sin37

F = 300 N

so it apply 300 N force along the inclined plane

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<h3>What is de Broglie wavelength?</h3>

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A mass oscillates up and down on a vertical spring with an amplitude of 3 cm and a period of 2 s. What total distance does the m
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Explanation:

It is given that,

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Answer:

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Where \mu represent the friction coefficient between the ground and the object.

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If we don't have any other forces involved in the y axis we can conclude that:

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And as we can see we have that Action force = Reaction force

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Explanation:

For this case we have this:

Action force: Would be the force of your feet against the Earth given by the weight defined as:

W = mg

Where g is a constat who represent the gravity g =9.8 m/s^2 in Earth

Reaction force: Would be the force of the Earth pushing against your feet. And on this case is represented by the normal force defined as:

N = \mu f_f

Where \mu represent the friction coefficient between the ground and the object.

And f_f the friction force.

If we don't have any other forces involved in the y axis we can conclude that:

W=N= mg

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Answer:

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Explanation:

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