Question

"An elevator is moving upward with a speed of 11 m/s. Three seconds later, the elevator is still moving upward, but its speed has been reduced to 5.0 m/s. What is the average acceleration of the elevator during the 3.0 s interval?

Answer 1

Answer:

Average acceleration = - 2 m/s^2

Explanation:

Given data:

Initial velocity = 11 m/s

Final velocity = 5.0 m/s

duration of change in velocity = 3 sec

Average acceleration $= \frac{v - u}{\Delta t}$

Average acceleration $= \frac{5 - 11}{3} = -2 m/s^2$

Average acceleration = - 2 m/s^2

here negative sign indicate that acceleration is proceed in downward direction.