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natita [175]
4 years ago
15

Where are mid-ocean ridges formed?

Physics
1 answer:
Verizon [17]4 years ago
8 0
Your answer is letter b
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An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic sound that travels 1530 m/s in seawater. find the dept
kompoz [17]
<span> It will travel 1530 m* 6 seconds =9180m. thus the depth there will be 9180/2=4590m.</span>
3 0
4 years ago
0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for
Paladinen [302]

Assuming the accleration applied was constant, we have

v=v_0+at\implies v_0+20.0\,\dfrac{\mathrm m}{\mathrm s}=v_0+a(0.10\,\mathrm s)

\implies20.0\,\dfrac{\mathrm m}{\mathrm s}=a(0.10\,\mathrm s)

\implies a=200\,\dfrac{\mathrm m}{\mathrm s^2}

Then the force applied to the ball is given by

F=ma=(0.45\,\mathrm{kg})\left(200\,\dfrac{\mathrm m}{\mathrm s^2}\right)

\implies F=90\,\dfrac{\mathrm{kg}\,\mathrm m}{\mathrm s^2}=90.\,\mathrm N

8 0
3 years ago
when the driver touches A Car steering wheel on a hot day heat is transferred to the driver's Hands by
Masteriza [31]
Heat is transferred to the driver's hands by conduction. The direct contact between the steering wheel and the driver's hands allows heat from molecules on the surface of the steering wheel to transfer to the molecules on the surface of the driver's hands. This is in contrast to convection (which requires a fluid in between the two surfaces that transfers heat).
5 0
3 years ago
Joe applies a force of 50 N to a box which has a mass of 15 kg. What is the acceleration of the box?
Allushta [10]

Answer:

3.333 m/s^2

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6 0
3 years ago
Find our the total distance between those 2 womens after 100 seconds. Refer the image for the full question ASAP. Give me a comp
diamong [38]
<h3>Given</h3>

\small\bf\red{First\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 15m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}

\small\bf\green{Second\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 20m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}

<h3>To Find</h3>

\:\:\:\:\bullet\:\:\sf{Distance \: between \:them \:after \:{\sf{\blue{100 \:seconds}}}} \\

<h3>Solution </h3>

\\→\:\:\:\sf Distance\: travelled \:by \:1st \:women\: = \: Velocity \times Time\:taken

→\:\:\:\sf 15 \times 100

→\:\;\:\sf 1500m

→\:\:\:\sf s_{1} = {\sf{\red{1500m}}} \\ \\

\Rightarrow\:\:\:\sf Distance \:travelled \:by\: 2nd \:women\: = \: Velocity \times Time\:taken

\Rightarrow\:\:\:\sf 20 \times 100

\Rightarrow\:\:\:\sf  2000m

\Rightarrow\:\:\:\sf s_{2} = {\sf{\purple{2000m}}} \\ \\

\small{\underline{\bf{Now, \:Distance \:between \:them\: =\: s_{2} - s_{1}}}_{}}

\hookrightarrow\:\:\:\sf 2000 - 1500

\hookrightarrow\:\:\:\bf \pink{500m} \\ \\

{\underline{\bf{Hence, }}}

Total Distance between them after \bf{100 \:seconds} is \bf\orange{500m}

3 0
3 years ago
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