Question

An ideal gas is contained in a container of volume V at temperature T. If the volume is doubled at a constant pressure, what will be the change in temperature?

Answer 1

The temperature will be doubled.

Answer 2

Answer: The temperature also get doubled.

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$    (At constant pressure and number of moles)

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1$ = initial volume of gas = v

$V_2$ = final volume of gas = 2v

$T_1$ = initial temperature of gas = t

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{v}{t}=\frac{2v}{T_2}$

$T_2=2t$

Therefore, the temperature of the gas of will be twice of initial temperature.