Answer:
The surface area is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The surface area of a triangular prism is equal to
where
B is the area of the triangular base
P is the perimeter of the triangular face
H is the height of the prism
<em>Find the area of the base B</em>
<em>Find the perimeter of the base P</em>
we have
substitute the values
The surface area is
Answer:
The third quartile is 56.45
Step-by-step explanation:
The given parameters are;
The first quartile, Q₁ = 30.8
The median or second quartile, Q₂ = 48.5
The mean, = 42.0
Coefficient of skewness = -0.38
The Bowley's coefficient of skewness (SK) is given as follows;
Plugging in the values, we have;
Which gives;
-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5
11.704 - 0.38·Q₃ = Q₃ - 66.2
1.38·Q₃ = 11.704 + 66.2 = 77.904
Q₃ = 56.45
The third quartile = 56.45.