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3 years ago

Which type of wave would actually slow down when moving from the air into the ocean?

Physics

2 answers:

stiv31 [10]3 years ago

8 0

The correct answer to the question is : Light or any electromagnetic wave.

EXPLANATION :

Before going to answer this question, first we have to understand refraction.

Refraction is the optical phenomenon in which light ray will bend at the interface of the two media having different optical densities.

When light ray comes from optical rarer medium to optical denser medium, the ray will bend towards the normal. It is so because the velocity of light in rarer medium is more than velocity of light in denser medium.

When the light comes from optical denser medium to optical rarer medium, the light ray bends away from the normal. It is so because the velocity of light increases in the rarer medium.

As per the question, wave is moving from air to ocean, and its velocity slows down.

Hence, there is refraction. So, the wave must be light or any electromagnetic wave.

kvasek [131]3 years ago

5 0

Any electromagnetic wave, like light or heat.

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What is the wave speed of a 1,000 Hz wave with a wavelength of 0.04 m?

dalvyx [7]

Wave speed = 40 m/s

Explanation:

Wave speed = frequency x wavelength

Wave speed = 1000 * 0.04

Wave speed = 40 m/s

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3 years ago

a race car accelerates uniformly from 18.5m/s to 46.1m/s in 2.4 seconds. determine the acceleration of the car and the distance

8_murik_8 [283]

The car's (average) acceleration would be

$a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}$

The car's position over time would be given by

$x=v_0t+\dfrac12at^2$

so that after 2.4 seconds, the car will have traveled a distance of

$x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2$

$\implies x=77.5\,\mathrm m$

7 0

3 years ago

Read 2 more answers

How can the distance between the first bright band and the central band be increased in a double-slit experiment?

Strike441 [17]

Answer:

Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.

Explanation:

The distance $y$ from the central band to the first bright band is given by

$y = \dfrac{ \lambda D}{d}$

where $\lambda$ is the wavelength of light (or any particle), $D$ is the distance to the screen, and $d$ is the slit separation.

From this equation we see that, by increasing the wavelength $\lambda$ , increasing the distance from the screen $D$ , and decreasing the slit separation $d$ , we increase the distance between the first bright band and the central band.

Therefore, the 2nd choice "Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength." is correct.

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4 years ago

A thin electrical heating element provides a uniform heat flux qo" to the outer surface of a duct through which air flows. The d

Ivanshal [37]

Answer:

a)q= 2800 W/m²

b)To=59.4°C

Explanation:

Given that

L = 10 mm

K= 20 W/m·K

T=30°C

h= 100 W/m²K

Ti=58°C

Heat flux q

q= h ΔT

q= 100 x (58 - 30 )

q= 2800 W/m²

As we know that heat transfer by Fourier law given as

Q= K A ΔT/L

Lets take outer temperature is To

So by Fourier law

To= Ti + qL/K

Now by putting the values

To= Ti + qL/K

$To= 58 + 2800 \times \dfrac{ 0.01}{20}$

To=59.4°C

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3 years ago

In deep space (no gravity), the bolt (arrow)

salantis [7]

t = 0.527 s

It accelerates for 0.527 s.

Explanation:

We use the formula:

v = u+at

Given:

v = 106 m/s

u = 0 (since no gravity)

$a=201 \mathrm{m} / \mathrm{s}^{2}$

So applying the formula,

v = u+at

106 = 0 + 201t

t = 106/201

t = 0.527 s

4 0

3 years ago