What is the entropy change associated with the expansion of one mole of an ideal gas from an initial volume of v to a final volu
1 answer:
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Answer:
r = 0.11 m
Explanation:
The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (), as follows:
(1)
<u>Where:</u>
<em>m: is the proton's mass = 1.67*10⁻²⁷ kg</em>
<em>v: is the proton's velocity</em>
<em>r: is the radius of the proton's orbit</em>
<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>
<em>B: is the magnetic field = 0.040 T </em>
Solving equation (1) for r, we have:
(2)
By conservation of energy, we can find the velocity of the proton:
(3)
<u>Where:</u>
<em>K: is kinetic energy</em>
<em>U: is electrostatic potential energy</em>
<em>ΔV: is the potential difference = 1.0 kV </em>
Solving equation (3) for v, we have:
Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:
Therefore, the radius of the proton's resulting orbit is 0.11 m.
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Answer:
Angular acceleration, is
Explanation:
Given that,
Initial speed of the drill,
After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed,
We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.
So, the drill's angular acceleration is .