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3 years ago

15

Choose all the answers that apply.

2 answers:

kicyunya [14]3 years ago

6 0

Metamorphic rock. I had this question last year. I hope I helped!

goldfiish [28.3K]3 years ago

6 0

Answer:

Option (2) and (3)

Explanation:

Sedimentary rocks are the rocks formed due to the compaction and lithification of sediments. According to the rock cycle, these <u>sedimentary rocks can change into both metamorphic as well as igneous rocks</u>.

Sedimentary rocks can turn into metamorphic rock if the rock is subjected to high-pressure and temperature conditions. For example, shale (sedimentary rock) changes into slate (metamorphic rock) due to the process of metamorphism.

The sedimentary rocks can also change into igneous rocks. When the sedimentary rock such as sandstone is subjected to extremely high pressure and temperature condition, then it starts to melt forming magma, and this magma when crystallizes (cools) it forms igneous rock. For example, granite.

Thus, the correct options are (2) and (3).

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3 years ago

Read 2 more answers

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8 0

3 years ago

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

3 years ago