<span>You are given a steel cylinder containing 25 kg of CCl2F2 in the form of liquid and vapor is set outdoors on a warm day 25 degrees celsius. The approximate pressure of the vapor in the cylinder 655mmHg.</span>
I am pretty sure that is exactly what you need. Proton in there should either gain or loss from the carbon, as there is <span>resonance stabilization. Do hope you still need the answer, because this one is really helpful. Regards!</span>
I believe this problem have these following choices:
5,000 cal
0.05 cal
5 x 10^3 cal
5 x 10 ^4 cal
<span>Now 1 kilocalorie = 1000
calories, therefore:</span>
50 kilocalories * (1000 calories / 1 kilocalorie) = 50,000 calories
Since there are 4 zeroes, so the scientific notation is:
5 x 10 ^4 cal (ANSWER)
Answer:
28.52 L
Explanation:
First, let's calculate the density of the ocean, which is the mass divided by the volume:
d = m/V
d = 35.06/1
d = 35.06 g/L
So, for a mass of 1.00 kg = 1000.00 g
d = m/V
35.06 = 1000.00/V
V = 1000.00/35.06
V = 28.52 L
How all the data are expressed with two significant figures, the volume must also be expressed with two.
Answer:
0.01 M
Explanation:
NaOH (sodium hydroxide) is a strong base, so it is completely dissociated into ions in aqueous solution:
NaOH ⇄ Na⁺ + OH⁻
So, we have OH⁻ ions in solution.
From the problem, we have the pH value. The pH is calculated as:
pH = -log [H⁺]
As NaOH is a base, we can also calculate the pOH:
pOH = -log [OH⁻]
Thus. we can use the relation between pH and pOH to calculate the pOH and then use it to calculate [OH⁻]:
pH + pOH = 14 ⇒ pOH = 14 - pH = 14 - 12.05 = 1.95
pOH = -log [OH⁻] ⇒ [OH⁻] =
=
= 0.0112 M ≅ 0.01 M