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SVEN [57.7K]
3 years ago
15

What is equivalent to 2 5/9

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

2.555555 ....

Step-by-step explanation:

2 5/9 is a mixed number.  

Use your calculator to divide 9 into 5, to find the value of 5/9.  Then add 2 to the result:

5/9 = 0.5555555 (repeating fraction)

Adding 2, we get:

2.555555 .... (repeating fraction)

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A volleyball team won 90% of 80 games played.how many games did they win?
andreyandreev [35.5K]

Answer:

72 games won

Step-by-step explanation:

4 0
3 years ago
What is the solution to –4(8 – 3x) ≥ 6x – 8?<br><br> x ≥ –<br> x ≤ –<br> x ≥ 4<br> x ≤ 4
ollegr [7]

Answer:

x ≥ 4

Step-by-step explanation:

–4(8 – 3x) ≥ 6x – 8

Distribute

-32 +12x ≥ 6x – 8

Subtract 6x from each side

-32 +12x-6x ≥ 6x-6x – 8

-32 +6x  ≥  – 8

Add 32 to each side

-32 +32 +6x≥ 32– 8

6x ≥ 24

Divide by 6

6x/6 ≥ 24/6

x ≥ 4

7 0
3 years ago
Read 2 more answers
Which graph shows the solution to the system of linear inequalities?
liberstina [14]

Answer:

?

Step-by-step explanation:

Sorry, can’t help. Not enough information :(

8 0
3 years ago
If f(x)=(2x^2)-1, find:<br> -f(3x-1)+2
Sergeeva-Olga [200]

Answer:

-f(3x - 1) + 2 = -18x² + 12x + 1

Step-by-step explanation:

Step 1: Find f(3x - 1)

f(3x - 1) = 2(3x - 1)² - 1

f(3x - 1) = 2(9x² - 6x + 1) - 1

f(3x - 1) = 18x² - 12x + 2 - 1

f(3x - 1) = 18x² - 12x + 1

Step 2: Plug in f(3x - 1)

-(18x² - 12x + 1) + 2

Step 3: Evaluate

-18x² + 12x - 1 + 2

-f(3x - 1) + 2 = -18x² + 12x + 1

8 0
3 years ago
Read 2 more answers
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
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