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tamaranim1 [39]
3 years ago
5

At a certain temperature and pressure, 0.20 mol of carbon dioxide has a volume of 3.1 L. A 3.1-L sample of hydrogen at the same

temperature and pressure ____. a. has the same mass b. contains the same number of atoms c. has a higher density d. contains the same number of molecules
Chemistry
1 answer:
Arada [10]3 years ago
7 0

A 3.1 L sample of hydrogen <u>d. contains the same number of molecules</u>

as 3.1 L of carbon dioxide at the same temperature and pressure.

This is the fundamental principle of <em>Avogadro’s hypothesis</em>: equal volume of gases at the same temperature and pressure contain the same number of molecules.

The sample of carbon dioxide has a <em>greater mass</em>, a <em>greater number of atoms</em>, and a <em>greater density</em>, than the sample of hydrogen.  

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The solubility of lead(II) iodide is 0.064 g/100 mL at 20ºC. What is the solubility product for lead(II) iodide?
quester [9]

Answer:

Ksp=1.07x10^{-8}

Explanation:

Hello,

In this case, the dissociation reaction is:

PbI_2(s)\rightleftharpoons Pb^{2+}(aq)+2I^-(aq)

For which the equilibrium expression is:

Ksp=[Pb^{2+}][I^-]^2

Thus, since the saturated solution is 0.064g/100 mL at 20 °C we need to compute the molar solubility by using its molar mass (461.2 g/mol)

Molar solubility=\frac{0.064g}{100mL}*\frac{1000mL}{1L}*\frac{1mol}{461.2g}=1.39x10^{-3}M

In such a way, since the mole ratio between lead (II) iodide to lead (II) and iodide ions is 1:1 and 1:2 respectively, the concentration of each ion turns out:

[Pb^{2+}]=1.39x10^{-3}M

[I^-]=1.39x10^{-3}M*2=2.78x10^{-3}M

Thereby, the solubility product results:

Ksp=(1.39x10^{-3}M)(2.78x10^{-3}M)^2\\\\Ksp=1.07x10^{-8}

Regards.

6 0
3 years ago
What current (in a) is required to plate out 1. 22 g of nickel from a solution of ni2 in 0. 50 hour?
Mashcka [7]

The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

<h3>What is current?</h3>

The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

\rm Ni^{2+}+2e^-\;\rightleftharpoons Ni

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

\rm 58.7\;g=2\;\times\;96487\;C\\58.7\;g=192974\;C

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

\rm 58.7\;grams\;Ni=192974\;C\\\\1.22\;grams\;Ni=\dfrac{192974}{58.7}\;\times\;1.22\;C\\\\1.22\;grams\;Ni=4010.7\;C

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

\rm Charge=Current\;\times\;Time\\4010.7\;C=Current\;\times\;1800\;sec\\Current=2.23\;A

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

Learn more about current, here:

brainly.com/question/23063355

#SPJ4

7 0
1 year ago
HELP MEEEE ASAP PLEASEEEE !!!!!!!!
jasenka [17]

Ok, I will help you answer but it is very hard to read could you enlarge it first?

Thanks!

5 0
3 years ago
Which of the following statements explains which trial has a lower concentration of the reactant? (5 points) Trial 1, because th
PIT_PIT [208]

Answer:

A)Trial 1 because the average rate of reaction is lower.

Explanation:

I accidentally gave myself low rating my bad

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