Answer:
Mass = 182.4 g
Explanation:
Given data:
Number of moles of Al₂O₃ = 3.80 mol
Mass of oxygen required = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Now we will compare the moles of aluminum oxide and oxygen.
Al₂O₃ : O₂
2 : 3
3.80 : 3/2×3.80 = 5.7
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 5.7 mol × 32 g/mol
Mass = 182.4 g
B .pure water it’s made up of oxygen and hydrogen “H2O”
Answer:
![FeCl_{3}](https://tex.z-dn.net/?f=FeCl_%7B3%7D)
Explanation:
mass of Fe = 55.85 g
Molar mass of Fe = 55.85 g/mol
<u>Moles of Fe = 55.85 / 55.85 = 1</u>
mass of Cl = 106.5 g
Molar mass of Cl = 35.5 g/mol
Moles of Cl = 106.5 / 35.5 = 3
Taking the simplest ratio for Fe and Cl as:
1 : 3
The empirical formula is = ![FeCl_{3}](https://tex.z-dn.net/?f=FeCl_%7B3%7D)
Answer: THE ANSWER IS OZONE WEEEE a layer in the earth's stratosphere at an altitude of about 6.2 miles (10 km) containing a high concentration of ozone, which absorbs most of the ultraviolet radiation reaching the earth from the sun.
Explanation:
Answer:
Heat flux = 13.92 W/m2
Rate of heat transfer throug the 3m x 3m sheet = 125.28 W
The thermal resistance of the 3x3m sheet is 0.0958 K/W
Explanation:
The rate of heat transfer through a 3m x 3m sheet of insulation can be calculated as:
![q=-k*A*\frac{\Delta T}{\Delta X}\\\\q=-0.029\frac{W}{m*K}*(3m*3m)*\frac{12K}{0.025m} =125.28W](https://tex.z-dn.net/?f=q%3D-k%2AA%2A%5Cfrac%7B%5CDelta%20T%7D%7B%5CDelta%20X%7D%5C%5C%5C%5Cq%3D-0.029%5Cfrac%7BW%7D%7Bm%2AK%7D%2A%283m%2A3m%29%2A%5Cfrac%7B12K%7D%7B0.025m%7D%20%20%3D125.28W)
The heat flux can be defined as the amount of heat flow by unit of area.
Using the previous calculation, we can estimate the heat flux:
![heat \, flux=\frac{q}{A}=\frac{125.28 W}{9 m^{2} } =13.92 W/m^{2}](https://tex.z-dn.net/?f=heat%20%5C%2C%20flux%3D%5Cfrac%7Bq%7D%7BA%7D%3D%5Cfrac%7B125.28%20W%7D%7B9%20m%5E%7B2%7D%20%7D%20%20%3D13.92%20W%2Fm%5E%7B2%7D)
It can also be calculated as:
![q/A=-k*\frac{\Delta T}{\Delta X}](https://tex.z-dn.net/?f=q%2FA%3D-k%2A%5Cfrac%7B%5CDelta%20T%7D%7B%5CDelta%20X%7D)
The thermal resistance can be expressed as
![\Delta T=R_t*Q\\R_t=\Delta T/Q=\frac{\Delta X}{k*A}](https://tex.z-dn.net/?f=%5CDelta%20T%3DR_t%2AQ%5C%5CR_t%3D%5CDelta%20T%2FQ%3D%5Cfrac%7B%5CDelta%20X%7D%7Bk%2AA%7D)
For the 3m x 3m sheet, the thermal resistance is
![R_t = \frac{\Delta X}{k*A}=\frac{0.025m}{0.029W/mK*9m^{2}}=0.0958 \, K/W](https://tex.z-dn.net/?f=R_t%20%3D%20%5Cfrac%7B%5CDelta%20X%7D%7Bk%2AA%7D%3D%5Cfrac%7B0.025m%7D%7B0.029W%2FmK%2A9m%5E%7B2%7D%7D%3D0.0958%20%5C%2C%20K%2FW)