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muminat
3 years ago
12

I WIll upvote for answer Balance the following reaction Fe^2 O ^3 +HCI->FeCI^3+H^2O

Chemistry
1 answer:
kotykmax [81]3 years ago
7 0
Fe^2 O^3 + 6HCl --> 2FeCl^3 + 3H^2 O
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How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
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You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

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Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

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