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muminat
3 years ago
12

I WIll upvote for answer Balance the following reaction Fe^2 O ^3 +HCI->FeCI^3+H^2O

Chemistry
1 answer:
kotykmax [81]3 years ago
7 0
Fe^2 O^3 + 6HCl --> 2FeCl^3 + 3H^2 O
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What are the molar concentrations of the ion in 0.26m aluminum sulfate? For c(so4^2-)
Alex777 [14]

Answer:

0.78 M for SO₄²⁻

Explanation:

The chemical formula for aluminium sulfate is Al₂(SO₄)₃

So for a concentration of 0.26 M you have in solution 0.26 moles of Al₂(SO₄)₃ in 1 liter of solution.

But you have three times more sulfate ions SO₄²⁻ in solution, so the molar concentration for this ion will be:

0.26 × 3 = 0.78 M

3 0
4 years ago
How much HCI exists in 275 mL of 0.83 M<br> solution of HCI?<br> Answer in units of mol.
zubka84 [21]

Answer:

0.22825mol HCl

Explanation:

M=\frac{moles}{liters} \\

0.83M HCl = \frac{x(mol)}{0.275L}

1. Cross multiply!

\frac{0.83M}{1} =\frac{x}{0.275L}

x = 0.22825 mol HCl

7 0
3 years ago
Suggest a reason why gold is expensive, even though it is found native in rock.​
Delvig [45]
Because it’s rare to find, and has a Extraordinary color that most rocks don’t have. Please mark as brainliest
6 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Setler [38]

Answer:

1. protons

2. hydrogen

3. protons plus neutrons

4. nuclear force

5. they are composite particles

6. proton-positive-inside nucleus; neutron-no charge-inside nucleus; electron-negative-outside nucleus/electron cloud

7. sublevels

8. 4 energy levels

Explanation:

3 0
3 years ago
How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?
valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

8 0
3 years ago
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