Ask question

Ask question

All categories

Marizza181 [45]

3 years ago

10

At what voltage would a () capacitor have the minimum energy to raise by ignoring all losses in the system? If needed, you may a

ssume a gravitational acceleration of 9.80 m/s2.

1 answer:

Charra [1.4K]3 years ago

8 0

Answer:

V = 280.15 V

Explanation:

" The complete question is attached with figure"

Given:

- The capacitance of the capacitor C = 10 nF

- The amount of mass attached to motor m = 4 grams

- The amount of distance it is to be lifted h = 1 cm

- Ignore all other losses in the system

Find:

- The voltage required to lift the mass m through distance h?

Solution:

- The conservation of energy for the entire system is written as:

Work_gravity = U_c

Where,

Work_gravity: Work done by gravity on mass m

U_c: The amount of energy stored in a capacitor

m*g*h = 0.5*C*V^2

V^2 = 2*m*g*h / C

V = sqrt ( 2*m*g*h / C )

Plug in the values:

V = sqrt ( 2*0.004*9.81*0.01 / 10*10^-9 )

V = sqrt ( 78,480)

V = 28.15 V

You might be interested in

Martha has been running a small business for two years. She now seeks additional investment to finance her business. She has fou

Dafna11 [192]

Answer:

The correct option is B) Balance Sheet

Explanation:

A Balance Sheet offers a description of a company's obligations, assets, and investments as well as net income over a given span of time such as a period of 6 months or 12 months, for instance.

Also known as the Statement of Financial Position, it contains sufficient information for investors and business owners to determine the company's financial performance in that period as well as to compare the performance of that company with industry norms or competition.

Cheers

8 0

3 years ago

Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an

Lera25 [3.4K]

Answer:

$\dot Q_{out} = 13369.104\,kW$

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

$-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0$

The rate of heat transfer between the turbine and its surroundings is:

$\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}$

The specific enthalpies at inlet and outlet are, respectively:

$h_{in} = 3076.41\,\frac{kJ}{kg}$

$h_{out} = 2675.0\,\frac{kJ}{kg}$

The required output is:

$\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW$ $\dot Q_{out} = 13369.104\,kW$

4 0

3 years ago

Question #6 Fill in the Blank Complete the following sentence. The term describes initiatives and products that preserve the env

viktelen [127]

Answer:

The term "<u>green"</u> describes initiatives and products that preserve the environment

Explanation:

In order to preserve the environment the Environmental Protection Agency has provides tips for "Being Green on the Road", which highlights the topics including, Green Vehicle Guides, guides for Fuel Economy, guides for Clean Diesel and many more ways our environmental footprint can be reduced

A green economy is an economy that focuses on the reduction of risk of economic activity on the environment, such as the reduction of carbon emission and reduction in environmental pollution, biodiversity loss prevention, and promotes a sustainable development

A green tech aims to protect the environment and to reverse previous damage done to the environment, including technology for clean energy, water purification, and waste recycling.

6 0

3 years ago

In a production facility, 3 cm thick large brass plates (k = 110 W/mC, α = 33.9 × 10-6 m2 /s) that are initially at a uniform

zysi [14]

Answer:

Explanation:

Given.

Thickness of brass plate $t = 3 cm$

Thermal conductivity of brass $k = 110 W/m.°C$

Density of brass $\rho = 8530 kg/m^3$

Specific heat of brass $C_p =380J/kg.°C$

Thermal diffusivity of brass $\alpha = 33.9\times 10^{-6} m^2/s$

Temperature of oven $T_{\infty} = 700°C$

The initial temperature $T_i= 25°C$

Plate remain in the oven $t =10 min$

Heat conduction in the plate is one-dimensional since the plate is large relative to its thickness and there is thermal symmetry about the center plane.

The thermal properties of the plate are constant.

The heat transfer coefficient is constant and uniform over the entire surface.

The Fourier number is > 0.2 so that the one-term approximate solutions (or the transient temperature charts) are applicable (this assumption will be verified).

The Biot number for this process $Bi = \frac{hL}{k}\\\\Bi=\frac{(80 W/m^2.°C)(0.015 m)}{(110 W/m.°C)}\\=Bi =0.0109$

The constants $\lambda_1$ and $A_1$ corresponding to this Biot are, from 11-2 tables.

The interpolation method used to find the

$\lambda_1=0.1039$ and $A_1=1.0018
$

The Fourier number $\tau=\frac{\alpha t}{L^2}\\\\\tau=\frac{(33.9\times 10^{-6} m^2/s)(10 min \times 60 s/min)}{(0.015m)^2}
\\\\\tau=90.4>0.2$

Therefore, the one-term approximate solution (or the transient temperature charts) is applicable.

Then the temperature at the surface of the plates becomes

$\theta(L,t)_{wall}=\frac{T(x,t)-T_{\infty}}{(T_i-T_{\infty})}\\\\\theta(L,t)_{wall}=A_1e^{-\lambda_1^2\tau}\cos(\lambda_1L/L)\\\\\theta(L,t)_{wall}=(1.0018)e^{-(0.1039^2(90.4))}\cos(0.1039)\\\\\theta(L,t)_{wall}=0.378\\\\\frac{T(L,t)-700}{25-700}=0.378\\\\T(L,t)=445°C$

3 0

3 years ago

Read 2 more answers

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi

yan [13]

Answer:

The filled in codes are

1) private static int[] arr;

2) int arr[] = new int[size_of_array];

int increment = 100;

for (int i = 0; i < size_of_array; i++) {

arr[i] = increment * i;

}

return arr;

3) for (int i = 0; i < myArray.length; i++) {

System.out.println(myArray[i]);

4) OneDimensionalArrays result = new OneDimensionalArrays();

result.createIntegers(num);

result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

int[] createIntegers(int size_of_array)

{

//******* FILL IN CODE *********

// Your code will create an array of ints as large as specified in size_of_array

// Fill the array in with the values: 0, 100, 200, 300, ....

// Return the array that you just created

}

void printArray(int[] myArray)

{

//******* FILL IN CODE *********

// Print out your array with one number per line. Get the size of the

// array from the "myArray" parameter (no hard coding the size)

}

public static void main(String[] args) {

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter size of array to create: ");

int num = keyboard.nextInt();

//******* FILL IN CODE *********

// Construct an instance of the OneDimensionalArrays class

// Using this object instance, call createIntegers to create

// an array of integers. Don't forget to save the results

// Then call the printArray method to print out the contents

// of your array.

}

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

private static int[] arr;

int[] createIntegers(int size_of_array) {

int arr[] = new int[size_of_array];

int increment = 100;

for (int i = 0; i < size_of_array; i++) {

arr[i] = increment * i;

}

return arr;

}

void printArray(int[] myArray) {

for (int i = 0; i < myArray.length; i++) {

System.out.println(myArray[i]);

}

}

public static void main(String[] args) {

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter size of array to create: ");

int num = keyboard.nextInt();

OneDimensionalArrays result = new OneDimensionalArrays();

result.createIntegers(num);

result.printArray(arr);

}

}

7 0

3 years ago