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Kisachek [45]
3 years ago
13

What are the 2 reasons an alignment should be done?

Engineering
1 answer:
NikAS [45]3 years ago
5 0

Answer:

because it will keep the tires in much better shape and it can improve the handling and keep your  car from pulling to one side

Explanation:

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Doubling the diameter of a solid, cylindrical wire doubles its strength in tension.
julsineya [31]

Answer:

True ❤️

-Solid by solid can make Cylindrical wire doubles Strengths in tension

4 0
3 years ago
If he wants to keep the height the same, what could the other dimensions be for him to get the volume he wants?
Fiesta28 [93]

tbm queria saber essa pergunta

8 0
3 years ago
Engineers will redesign their products when they find flaws. TRUE O False​
nataly862011 [7]

Answer:

true

Explanation:

6 0
3 years ago
A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated
Rzqust [24]

Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

7 0
3 years ago
The volume of 1.5 kg of helium in a frictionless piston-cylinder device is initially 6 m3. Now, helium is compressed to 2 m3 whi
coldgirl [10]

Answer:

The initial temperature will be "385.1°K" as well as final will be "128.3°K".

Explanation:

The given values are:

Helium's initial volume, v₁ = 6 m³

Mass, m = 1.5 kg

Final volume, v₂ = 2 m³

Pressure, P = 200 kPa

As we know,

Work, W=p(v_{2}-v_{1})

On putting the estimated values, we get

⇒            =200000(2-6)

⇒            =200000\times (-4)

⇒            =800,000 \ N.m

Now,

Gas ideal equation will be:

⇒  pv_{1}=mRT_{1}

On putting the values. we get

⇒  200000\times 6=1.5\times 2077\times T_{1}

⇒  T_{1}=\frac{1200000}{3115.5}

⇒       =385.1^{\circ}K (Initial temperature of helium)

and,

⇒  pv_{2}=mRT_{2}

On putting the values, we get

⇒  200000\times 2=1.5\times 2077\times T_{2}

⇒  T_{2}=\frac{400000}{3115.5}

⇒       =128.3^{\circ}K (Final temperature of helium)

3 0
3 years ago
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