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Art [367]
3 years ago
5

If you deposit today 11,613 in an account earning 8% compound interest, for how long should you invest the money in order to ear

n 15,131.76 (profit)?
Engineering
1 answer:
Elanso [62]3 years ago
3 0
Y = a (b)^t/p

y is total money

a is original amount

b is growth / decay factor

t is time

p is the frequency of every growth or decay

15131.76 = 11613 x 1.08^x

15131.76 / 11613 = 1.08^x

1.303… = 1.08^x

log1.303…. = xlog1.08

x = 3.43902165741 years
You might be interested in
use engineering judgement to estimate the size of cooling and heating equipment that is needed for a three story, 31,000 square
Blizzard [7]

Answer: operating cost = 22820.736 $

Energy = 32.291 KBtu/sf.

Explanation:

Total heating load is given as = 31000 * 31.25  

 = 968.75* 103 Btu

From the cooling capacity application;

If 1000ftsquare = 2.8 TR

Therefore 30000ftsquare = x

Where x is the total cooling load,

Therefore x = (30000 * 2.8) / 1000

x = 84TR.

Therefore, the total cooling load, x = 84TR

Using conversion factor;

i.e. converting Btu/hr to MBH

1 MBH = 1000 Btu per hour

we have 968.75* 103 Btu/hr = 968.75 MBH

let us proceed.

Estimating the “Annual operating cost” we first calculate the maximum operating cost (Avg/Annum)

For cooling load:

Max. operatn. Cost = 14 * 84 = 1176$

For heating load:

The average heating loading hours = 1000 hrs.

Conversion to Btu/yr gives = 968.75* 103 * 1000  

 = 968.75* 106 Btu/yr.

Conversion of 968.75* 103Btu to Kwh gives  

1Btu = 0.000293

968.75* 103 Btu = 283.84 Kwh  

Therefore, average cost gives;

(8.04/100) $ = 1Kwh

X = 283.84*103

X = 22820.736 $

Operating cost = 22820.736 $

Energy use in KBtu/sf is given as  

E = 968.75* 103 / 30000  

E = 32.291 KBtu/sf.

8 0
4 years ago
Kieran and Kurt spend most of their day performing physical labor, aligning materials, and inspecting projects for quality and s
xxMikexx [17]

Answer:

Kieran is a Carpenter, and Kurt is a Drafter

Explanation:

Among all the professions listed, Kurt can only possibly be a Drafter.  A Drafter is an engineering technician who makes detailed technical drawings or plans for machinery, buildings, electronics, infrastructure, sections, etc. Drafters make use of computer software and manual sketches to convert the designs, plans, and layouts of engineers and architects into a set of technical drawings. All the other professions will at some point need for the professional to stand and work at an height above the ground except for a drafter, whose feet will remain on the ground at almost all times.

5 0
3 years ago
Read 2 more answers
In crash tests, a shock absorber is used to slow the test car. The shock absorber consists of a piston with small holes that mov
Lesechka [4]

Answer:

The heat transferred to water equals 1600 kJ

Explanation:

By the conservation of energy we have

All the kinetic energy of the moving vehicle is converted into thermal energy

We know that kinetic energy of a object of mass 'm' moving with a speed of 'v' is given by

K.E=\frac{1}{2}mv^{2}

Thus

K.E_{car}=\frac{1}{2}\times 2000\times 40^{2}=1600\times 10^{3}Joules

Thus the heat transferred to water equals 1600kJ

3 0
3 years ago
How do robots demonstrate the modern, technological Japan? *<br><br><br><br>​
Alborosie

Robots demonstrate modern, technological Japan because it serves as brought economical success to Japan since it help them to build products faster and efficiently.

  • According to the question, we are to discuss how the robot help japan in terms of technology and modernization.

As a result of this we can see that Japan is moving forward in technology with development of robot because it makes them to build more products.

Therefore, Robot has  brought economical success to Japan

Learn more about robot at:

brainly.com/question/10387419

3 0
3 years ago
Read 2 more answers
Consider a step pn junction made of GaAs at T = 300 K. At zero bias, only 20% of the total depletion region width is in the p-si
Nat2105 [25]

Answer:

0.31 μm

Explanation:

this question wants us to Determine the depletion region width, xn​, in the n-side in unit of μm. using the information below.

density in the p-side = 5.68x10^16

density in the n-side = 1.42x10^16

\sqrt{\frac{2*12.7*8.85E-10}{1.6E-14}(\frac{1}{5.68E16}+\frac{1}{1.42E16} )(1.2)  }

= √(1.42x10⁵)(1.76056335x10⁻¹⁷ + 7.042253521x10⁻¹⁷)(1.2)

= √150.74x10⁻¹¹

= 3.882x10⁻⁵

approximately 0.39μm

xn = 0.39 x 0.8

= 0.31μm

0.31 um is the depletion region width. thank you!

3 0
3 years ago
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