Answer:
10.8 s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Acceleration (a) = 5 m/s/s
Distance travelled (s) = 291 m
Time (t) taken =?
We can calculate the time taken for the car to cover the distance as follow:
s = ut + ½at²
291 = 0 × t + ½ × 5 × t²
291 = 0 + 2.5 × t²
291 = 2.5 × t²
Divide both side by 2.5
t² = 291 / 2.5
t² = 116.4
Take the square root of both side
t = √116.4
t = 10.8 s
Thus, it will take the car 10.8 s to cover the distance.
Two disadvantages Retooling and conversion of machines and equipment in the US would be very expensive
Some expressions in the English language would eventually be quite strange: “A miss is as good as a mile”; “Inching along…”; “Ten gallon hat”; “The whole nine yards” & etc. Advantages everything is based on 10 so its easy to switch units
scientists can share info internationally
The poles don’t receive direct sunlight which is why they are colder than the tropics. Even during the summer the sun is low on the horizon.
Answer:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that
P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows
therefore, T_2= 234.37 K
Answer:
a. 1.027 x 10^7 m/s b. 3600 V c. 0 V and d. 1.08 MeV
Explanation:
a. KE =1/2 (MV^2) where the M is mass of electron
b. E = V/d
c. V= 0 V (momentarily the pd changes to zero)
d KE= 300*3600 v = 1.08 MeV
