Question

A 1,100 kg car comes uniformly to a stop. If the vehicle is accelerating at -1.2 m/s2, which force is closest to the net force acting on the vehicle?

Answer 1

Answer:

F= 1320 N

Explanation:

Given that

mass ,m= 1100 kg

Acceleration ,a= 1.2 m/s²

We know that ,According to the second law of Newton's

Force = Mass x acceleration

F= m a

F=Force ,a=acceleration

m=mass

Now by putting the values in the above equation

$F= 1100\times 1.2\ N$

F= 1320 N

Therefore the force on the vehicle will be 1320 N.