Question

What is the change in internal energy (in J) of a system that releases 954 J of thermal energy to its surroundings and has 166 cal of work done on it

Answer 1

Answer:

259.456 J

Explanation:

Given that,

Work done on the system = 166 cal

The systam releases 954 J of thermal energy to its surroundings

We need to find the change in internal energy. It can be given by using the first law of thermodynamics as follows :

$\Delta U=Q-W$

W = 166 cal = 694.544 (1cal = 4.184 J)

$\Delta U=954-694.544\\\\=259.456\ J$

So, the change in internal energy of the system is 259.456 J.