A 1.0-kilogram ball is dropped from the roof of a building 40. meters tall. What is the approximate time of fall? [Neglect air r
2 answers:
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Average velocity = Total Displacement / Total time taken
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =
= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =
= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
Answer:
D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.
Explanation:
As we know by newton's II law we have
so we will have
F = net force on the system
= change in momentum
so we can say if the momentum is conserved or the initial momentum of the system will be equal to the final momentum of the system
then we will say that
so net force on the system must be ZERO
so in such type of questions the system must be isolated and there is no external force on it
so correct answer will be
D. in a closed system, an object's momentum before a collision will equal its momentum after the collision.
Answer:
The speed of water flow inside the pipe at point - 2 = 34.67 m / sec
Explanation:
Given data
Diameter at point - 1 = 3.2 cm
Velocity at point - 1 = 1.1 m / sec = 110 cm / sec
Diameter at point - 2 = 0.57 cm
Velocity at point - 2 = ??
We know that from the continuity equation the rate of flow is constant inside a pipe between two points.
Thus
⇒ ×
=
×
⇒ ×
×
=
⇒ ×
=
×
⇒ × 110 =
×
⇒ = 3467 cm / sec
⇒ = 34.67 m / sec
Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec