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svetoff [14.1K]
3 years ago
11

What is the process in which triglycerides react with a strong, inorganic base such as sodium hydroxide to produce carboxylate s

alt and glycerol?
Chemistry
1 answer:
alexira [117]3 years ago
5 0
I believe that saponification is the process in which triglycerides react with a strong, inorganic base such as sodium hydroxide to produce carboxylate salt and glycerol. The process is the making of soap by reacting triglycerides with a strong base to form glycerol and soap. Soaps are sodium or potassium salts of long chain fatty acids. When triglycerides in fat/oil react with aqueous NaOH or KOH, they are converted into soap and glycerol.
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What is the name of the following compound? A line-angle formula shows a ring with six vertices and a circle inscribed. A Cl ato
ozzi

Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.

Explanation:

A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.

Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as <em>para </em>or <em>p </em>configuration.

Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).

Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.

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Answer:

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Explanation:

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What is the pressure in a 5.00 L tank with<br> 7.10 moles of oxygen at 39.3 °C?
Katena32 [7]

Answer:

36.4 atm

Explanation:

To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = ? atm                         R = 0.0821 L*atm/mol*K

V = 5.00 L                       T = 393 °C + 273.15 = 312.45 K

n = 7.10 moles

PV = nRT

P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)

P(5.00 L) = 182.130

P = 36.4 atm

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What is the volume of 12.0 moles of Cl2 gas at STP?
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