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3 years ago

The density of a substance is 4.8 g/mL. What is the volume of the sample that is 19.2 g?

Chemistry

1 answer:

mixas84 [53]3 years ago

5 0

Answer:

The answer is 4

Explanation:

You divide the grams by the volume which will give you the density

so 19.2 divided by 4.8 equals 4

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Can you Convert 75°F to °C

Leya [2.2K]

Answer: 23.8889

Explanation:

(75°F − 32) × 5/9 = 23.889°C

5 0

3 years ago

How much energy will it take to raise the temperature of 75.0 g of water from 20.0°C to 55.0°C?

Hatshy [7]

Answer:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:

ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C

given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

= heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

6 0

3 years ago

A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol

Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

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3 years ago

Flourine is more reactive than chlorine . why ? with short reason.

Talja [164]

Answer:

Electronegativity is probably the biggest thing that plays into reactivity. Therefore, since fluorine has a higher electronegativity than chlorine, fluorine is more reactive.

Explanation:

I got it right

7 0

3 years ago

What's what's the Lewis structure for 2H2O

Umnica [9.8K]

Lewis Structure:

H -- O -- H (bent, Oxygen has 2 lone pairs)

Percent Composition

Hydrogen percent composition = [ 2 * (Hydrogen mass) ] / [Total mass of H2O]

Oxygen percent composition = [Oxygen mass] / [Total mass of H2O]

dose this make any sense...??

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3 years ago