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Wewaii [24]
3 years ago
11

A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 12-m-long cable. You are (un

wisely!) standing directly beneath the point from which the wrecking ball is hung when you notice that the ball has just been released and is swinging directly toward you. How much time do you have to move out of the way?
Physics
2 answers:
leva [86]3 years ago
8 0
Because you know that gravity is in m/s^2 so, period will be measured in seconds. You know the cable is 12m long and gravity is 9.81 solve for T (period) 2π12sqrt(9.81)=6.94922
lisov135 [29]3 years ago
8 0

Answer:

Time to move out of the way = 1.74 s

Explanation:

This case is similar to simple pendulum. The period of simple pendulum is given by 2\pi \sqrt{\frac{l}{g} }.

 Period of wrecking ball =2\pi \sqrt{\frac{l}{g}}=2\pi \sqrt{\frac{12}{9.81}}=6.95s

 Time to move out of the way is one fourth of period = 6.95/4 = 1.74 seconds.

 Time to move out of the way = 1.74 s

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What is ozone? How and where is it formed in the atmosphere?
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3 years ago
A ball rolls horizontally off a table and a height of 1.4 m with a speed of 4 m/s. How long does it take the ball to reach the g
Hitman42 [59]

For vertical motion, use the following kinematics equation:

H(t) = X + Vt + 0.5At²

H(t) is the height of the ball at any point in time t for t ≥ 0s

X is the initial height

V is the initial vertical velocity

A is the constant vertical acceleration

Given values:

X = 1.4m

V = 0m/s (starting from free fall)

A = -9.81m/s² (downward acceleration due to gravity near the earth's surface)

Plug in these values to get H(t):

H(t) = 1.4 + 0t - 4.905t²

H(t) = 1.4 - 4.905t²

We want to calculate when the ball hits the ground, i.e. find a time t when H(t) = 0m, so let us substitute H(t) = 0 into the equation and solve for t:

1.4 - 4.905t² = 0

4.905t² = 1.4

t² = 0.2854

t = ±0.5342s

Reject t = -0.5342s because this doesn't make sense within the context of the problem (we only let t ≥ 0s for the ball's motion H(t))

t = 0.53s

8 0
3 years ago
Read 2 more answers
10m= (5.0) + (.5)(9.8)(5.0)
Norma-Jean [14]
M=2.45 because you multiply out the equation on the right and divide by 10
8 0
3 years ago
Light travels faster in warmer air. On a sunny day, the sun can heat a road and create a layer of hot air above it. Let's model
AysviL [449]

Answer:

Explanation:

If we assume there is a sharp boundary between the two masses of air, there will be a refraction. The refractive index of each medium will depend on the relative speeds of light.

n = c / v

If light travels faster in warmer air, it will have a lower refractive index

nh < nc

Snell's law of refraction relates angles of incidence and refracted with the indexes of refraction:

n1 * sin(θ1) = n2 * sin(θ2)

sin(θ2) = sin(θ1) * n1/n2

If blue light from the sky passing through the hot air will cross to the cold air, then

n1 = nh

n2 = nc

Then:

n1 < n2

So:

n1/n2 < 1

The refracted light will come into the cold air at angle θ2 wich will be smaller than θ1, so the light is bent upwards, creating the appearance of water in the distance, which is actually a mirror image of the sky.

6 0
3 years ago
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