A bumblebee darts past at 3 m/s. The frequency of the hum made by its wings is 152 Hz. Assume the speed of sound to be 342 m/s.
2 answers:
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Answer:
a)
b)
Explanation:
The knowable variables are the initial hight and initial velocity
The equation that describes the motion of the ball is:
If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.
a) Solving for t, we are going to have two answers
a=-16
b=64
c=80
or
<em><u>Since time can not be negative the answer is t=6.378s </u></em>
b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too
First of all, we need to find the maximum hight and how much time does it take to reach it:
at maximum point the velocity is 0
Solving for t
Now, we must know how much distance does it take to reach maximum point
So, the ball pass the top of the building on its way down at 160 ft
Solving for t
or
Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building
Answer:
DL = 1.5*10^-4[m]
Explanation:
First we will determine the initial values of the problem, in this way we have:
F = 60000[N]
L = 4 [m]
A = 0.008 [m^2]
DL = distance of the beam compressed along its length [m]
With the following equation we can find DL
Note: The question should be related with the distance, not with the diameter, since the diameter can be found very easily using the equation for a circular area.