The answer is ultraviolet
Answer:
- <u>2.59 × 10⁻⁷ m = 259 nm</u>
Explanation:
You need to calculate the wavelength of a photon with an energy equal to 463 kJ/mol, which is the energy to break an oxygen-hydrogen atom.
The energy of a photon and its wavelength are related by the Planck - Einstein equation:
Where:
- h = Planck constant (6.626 × 10⁻³⁴ J . s) and
- ν = frequency of the photon.
And:
Where:
- c = speed of light (3.00 × 10⁸ m/s in vacuum)
- λ = wavelength of the photon
Thus, you can derive:
Solve for λ:
Before substituting the values, convert the energy, 463 kJ/ mol, to J/bond
- 463 kJ/ mol × 1,000 J/kJ × 1 mol / 6.022 × 10 ²³ atom × 1 bond / atom
= 7.69×10²³ J / bond
Substitute the values and use the energy of one bond:
- λ = 6.626 × 10⁻³⁴ J . s × 3.00 × 10⁸ m/s / 7.69×10²³ J = 2.59 × 10⁻⁷ m
The wavelength of light is usually shown in nanometers:
- 2.59 × 10⁻⁷ m × 10⁹ nm / m = 259 nm ← answer
Answer:
3,4–diethylheptane
Explanation:
To name the compound given in the question above, the following must be obtained:
1. Determine the functional group of the compound.
2. Determine the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent groups attached to the compound.
4. Give the substituent groups the lowest possible count by naming them alphabetically.
5. Combine the above to obtain the name of the compound.
Now, we shall name the compound given in the question above as follow:
1. The compound belongs to the alkane family since it has only single bonds.
2. The longest continuous carbon chain is 7 i.e the parent name of the compound is heptane.
3. The substituent group attached to the compound is ethyl (–CH2CH3). There are two ethyl groups attached to the compound.
4. The two ethyl group is at carbon 3 and 4 (i.e number from the right to the upper branch chain).
5. The name of the compound is:
3,4–diethylheptane.
