How many moles of gold are there in 3.73 x 10^24 atoms of gold?
1 answer:
Answer:
6.2moles of Gold
Explanation:
To solve this problem, we are going to use the mole concept approach.
Given that;
Number of atoms of gold is 3.73 x 10²⁴ atoms
Now;
In 1 mole of any substance, we have 6.02 x 10²³ atoms;
So;
If there 6.02 x 10²³ atoms in 1 mole of any substance;
3.73 x 10²⁴ atoms will contain = 6.2moles of Gold
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The percent yield of carbon dioxide will be 49.0 %.
<h3>Percent yield</h3>First, let's look at the equation of the reaction:
The mole ratio of octane to oxygen is 2:25.
Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol
Mole of 19.1 g oxygen = 19.1/32 = 0.60 mol
Thus, octane is limiting.
Mole ratio of octane to carbon dioxide = 2:16.
Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol
Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams
Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %
More on percent yield can be found here: brainly.com/question/17042787
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Answer: 1.36 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
To calculate the moles, we use the equation:
moles of solute=
The balanced reaction between barium hydroxide and perchloric acid:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is
We are given:
Putting values in above equation, we get:
Thus the concentration of the acid is 1.36 M