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disa [49]
3 years ago
9

If the cooling power remains constant, what will be the temperature of the system TB after it has been in the freezer for exactl

y 1 hour
Chemistry
1 answer:
serg [7]3 years ago
8 0

Answer:

The answer is "-50.424° C".

Explanation:

Given:

Time = 1 hour

TB=?

Formula:

TB= \frac{-T\times P}{m \times c_i}

time (T) = 1 hour

             = 3600 second

t=(3600 -t_2)

Calculating T_B:

\to T_B= \frac{-(3600 - t_2) 36.6}{0.250 \times 2090}\\

          = \frac{-(3600 - 2880) 36.6}{522.6}\\\\= \frac{-(720) 36.6}{522.6}\\\\= \frac{-720 \times 36.6}{522.6}\\\\= \frac{-26352}{522.6}\\\\= -50.424 ^{\circ} C

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An element is a pure substance in which there are how many kinds of atoms?
Ostrovityanka [42]

Answer:

One

Explanation:

An element is a pure substance in which there are only one kind of atom. Elements are distinct substances that cannot be split up into simpler substances.

Such substances consists of only one kind of atom. There are over a hundred known elements to date.

Generally, as a pure substance, the composition of an element is definite and they are homogenous in all parts.

8 0
3 years ago
A gas has a volume of 240 mL and a pressure of 0.99 atm. If the pressure is decreased to 0.951 atm, what is the new volume of th
irakobra [83]

V2 = 250 ml

Explanation:

Given:

P1 = 0.99 atm. V1 = 240 ml

P2 = 0.951 atm. V2 = ?

We can use Boyle's law to solve for V2

P1V1 = P2V2

V2 = (P1/P2)V1

= (0.99 atm/0.951 atm)(240 ml)

= 250. ml

6 0
3 years ago
Magnesium has three naturally occurring isotopes(Mg-24, Mg-25, and Mg-26). The atomic mass and natural abundance of Mg-24 are 23
xxMikexx [17]

Answer:

The answer to your question is below

Explanation:

Data

               Atomic mass               Abundance

Mg -24 =    23.9850                         79%

Mg -25 =    24.9858                         10%  

Mg - 26=          ?                                  ?

Process

1.- Find the abundance of Mg-26

The sum of the abundance of the three isotopes equals 100%

         

 Abundance Mg-24 + Abundance-Mg-25 + Abundance-26 = 100

            79 + 10 + Abundance-26 = 100

            Abundance Mg-26 = 100 -89

           Abundance Mg-26 = 11%

2.- Find the atomic mass of Mg-26, the average atomic mass is 24.31 amu

Average atomic mass = (abundance)(atomic mass- 24) + (abundance)

                                         (atomic mass-25) + (abundance)(atomic mass-26)

    24.31 = (0.79)(23.9850)+ (0.10)(24.9858) + (Atomic mass-26)(0.11)

    24.31 = 18.94815 + 2.4986 + 0.11(atomic mass-26)

    24.31 = 21.4342 + 0.11(atomic mass- 26)

    0.11(atomic mass-26) = 24.31 - 21.4342

    0.11(atomic mass-26) = 2.8758

    Atomic mass-26 = 2.8758/0.11

 <u>   Atomic mass-26 = 26.1436 amu</u>

8 0
3 years ago
Read 2 more answers
Please help me I will give you the brain thing and extra points. 2
oee [108]
I think it’s A but, don’t come at me if I’m wrong. Btw I read over it multiple times so this isn’t a random guess. Good luck tell me if you got it right
7 0
3 years ago
Read 2 more answers
How many moles are in 2.8x10^24 atoms of silicon?
sergejj [24]

Answer:

4.6 mol Si

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 2.8 × 10²⁴ atoms Si

[Solve] moles Si

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                   \displaystyle 2.8 \cdot 10^{24} \ atoms \ Si(\frac{1 \ mol \ Si}{6.022 \cdot 10^{23} \ atoms \ Si})
  2. [DA] Divide [Cancel like units]:                                                                        \displaystyle 4.64962 \ mol \ Si

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

4.64962 mol Si ≈ 4.6 mol Si

6 0
3 years ago
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