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guapka [62]
3 years ago
14

Write down the colours of the precipitates formed by reaction of aqueous caustic soda with solutions of: copper, zinc and ferric

salts.
Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

Metal Color

Cobalt Pink (when hydrated)

Copper Blue

Iron (II) Green pale

Iron (III) Reddish brown

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Ilya [14]
The definition of heat transfer through convection involves the movement of a fluid that causes heat to move away from a hear source. That being said, convection can take place in a lake, air inside, and air outside since both liquids and gasses are considered to be fluids. I hope this helps. Let me know if anything is unclear.
5 0
3 years ago
Read 2 more answers
Atoms and molecules are constantly in motion. The more energy the atom or molecule contains, the faster they move about. In whic
Rus_ich [418]

Answer:

Solid

Explanation:

5 0
2 years ago
How many molecules are in 7.34 g of Na2CO3
kenny6666 [7]

Answer:

The answer is 105.98844.

<h3>Explanation: </h3>

We assume you are converting between grams Na2CO3 and mole. You can view more details on each measurement unit: molecular weight of Na2CO3 or mol This compound is also known as Sodium Carbonate.

7 0
2 years ago
Which of the following transports information from the eye to the brain?
Marina CMI [18]

Answer:

c

Explanation:

c is the correct answer

4 0
2 years ago
Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04
evablogger [386]

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

8 0
3 years ago
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