Answer: 3r + 2b = 24
r + 3b = 16
Step-by-step explanation:
Let the red blocks be represented by r
Let blue blocks be represented by b
Since 3 red blocks and 2 blue blocks weigh 24 ounces. This will be:
3r + 2b = 24
1 red block and 3 blue blocks weigh 16 ounces. This will be:
r + 3b = 16
Therefore, the equation will be:
3r + 2b = 24
r + 3b = 16
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
The answer the this problem can be either 6/15 or 2/5
Answer:
Step-by-step explanation:
y = x²+3
y = 3x+1
x² + 3 = 3x +1
x² - 3x + 2 = 0
(x-2)(x-1) = 0
x = 2, 1
Two solutions
(2,7) and (1,4)
The value of x in the triangle is 28.1 degrees
<h3>How to solve for x?</h3>
The given triangle is a right triangle.
So, the relationship between the sides and angle x is:
sin(x) = opposite/hypotenuse
This gives
sin(x) = 8/17
Evaluate the quotient
sin(x) = 0.4706
Take the arc sin of both sides
Evaluate
x = 28.1
Hence, the value of x in the triangle is 28.1 degrees
Read more about right triangles at:
brainly.com/question/2437195
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