Answer:
0.3 Ω
Explanation:
Resistance (R) = V/I
R = 1.5/5
R = 15/50
= 3/10
= 0.3Ω
hope it helps :)
Answer: The exit temperature of the gas in deg C is .
The given data is as follows.
= 1000 J/kg K, R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)
= 100 kPa,
We know that for an ideal gas the mass flow rate will be calculated as follows.
or, m =
=
= 10 kg/s
Now, according to the steady flow energy equation:
= 5 K
= 5 K + 300 K
= 305 K
= (305 K - 273 K)
Therefore, we can conclude that the exit temperature of the gas in deg C is .
Browsing agent
Hope this helps!
use the dimensions shown in the figure
Bending stress at point 3.96 is \sigma_b = 1.37 psi
Given data:
Bending Moment M is 4.176 ft-lb = 50.12 in- lb
moment of inertia I = 144 inc^4
y = 3.96 in
putting all value to get bending stress
Bending stress at point 3.96 is = 1.37 psi
Option B
10,20,24,75,70,18,60,35
The first, second and third iteration of the loop will be as follows
insertion sort iteration 1: 20,24,10,75,70,18,60,35
insertion sort iteration 2:10,20,24,75,70,18,60,35
insertion sort iteration 3: 10,20,24,75,70,18,60,35