. If sulphur (IV) oxide and methane are

Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f

Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide ( $CO_{2}$ )= $(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}$

Percentage by mass of carbon = $\frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%$

Percentage by mass of oxygen = $\frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%$

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO $_{2}$

7 0

3 years ago

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Rain soaks into the soil or runs off into oceans, rivers, and lakes. ___________ which process is this

krok68 [10]

Answer:

The water falls to the earth as precipitation, such as rain, hail, sleet, and snow. When precipitation reaches the earth's surface, some of it will flow along the surface of the land and enter surface water like lakes, streams, and rivers, as runoff. The rest of it soaks or percolates into the soil, called

5 0

2 years ago

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

Answer: The value of equilibrium constant for the given reaction is 56.61

Explanation:

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 0.1 0.1

At eqllm: 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0

3 years ago

describe how the discoveries of scientist over time have contributed to our current understanding of atom

Olenka [21]

Answer:

In 1897, the British physicist J. J. Thomson (1856–1940) proved that atoms were not the most basic form of matter. He demonstrated that cathode rays could be deflected, or bent, by magnetic or electric fields, which indicated that cathode rays consist of charged particles (Figure 2.2.2 ). More important, by measuring the extent of the deflection of the cathode rays in magnetic or electric fields of various strengths, Thomson was able to calculate the mass-to-charge ratio of the particles. These particles were emitted by the negatively charged cathode and repelled by the negative terminal of an electric field. Because like charges repel each other and opposite charges attract, Thomson concluded that the particles had a net negative charge; these particles are now called electrons. Most relevant to the field of chemistry, Thomson found that the mass-to-charge ratio of cathode rays is independent of the nature of the metal electrodes or the gas, which suggested that electrons were fundamental components of all atoms.

Explanation:

5 0

3 years ago

Citric acid (h3c6h5o7) is a product of the fermentation of sucrose (c12h22o11) in air. determine the mass of citric acid produce

Alex

2.50 x 2/1 = 5 mol of Citric Acid
5 x (3+72+5+112) = 960g of Citric Acid

Answer: 960g of Citric Acid

6 0

3 years ago

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