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Natali [406]
3 years ago
12

When you whirl a small rubber stopper on a cord in a vertical circle, you find a critical speed at the top for which the tension

in the cord is zero. At this speed. the force of gravity on the object 1S itselfisufficient to supply the necessary centripetal force. How slowly can you swing a 15-g stopper like this so that It will just follow a circle with a radius of m?​
Physics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

  √(9.8/m) radians per second

Explanation:

The centripetal acceleration required for a radius of m is ...

  a = mω²

so, the angular speed required is ...

  ω = √(a/m) =  √(g/m) . . . . . where g is the acceleration due to gravity

  ω = √(9.8/m) . . . radians per second

__

The speed is independent of the mass. For a 1 m radius, the speed is about 29.9 RPM.

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1. A listener stands 20.0 m from a speaker that pumps out music with a power output of 100.0 W.
marta [7]

(1.a) The surface area being vibrated by the time the sound reaches the listener is 5,026.55 m².

(1.b) The intensity of the sound wave as it reaches the person listening is 0.02 W/m².

(1.c) The relative intensity of the sound as heard by the listener is 103 dB.

(2.a) The speed of sound if the air temperature is 15⁰C is 340.3 m/s.

(2.b) The frequency of the sound heard by the suspect is 614.3 Hz.

<h3>Surface area being vibrated</h3>

The surface area being vibrated by the time the sound reaches the listener is calculated as follows;

A = 4πr²

A = 4π x (20)²

A = 5,026.55 m²

<h3>Intensity of the sound</h3>

The intensity of the sound is calculated as follows;

I = P/A

I = (100) / (5,026.55)

I = 0.02 W/m²

<h3>Relative intensity of the sound</h3>

B = 10log(\frac{I}{I_0} )\\\\B = 10 \times log(\frac{0.02}{10^{-12}} )\\\\B = 103 \ dB

<h3>Speed of sound at the given temperature</h3>

v= 331.3\sqrt{1 + \frac{T}{273} } \\\\v = 331.3\sqrt{1 + \frac{15}{273} } \\\\v = 340.3 \ m/s

<h3>Frequency of the sound</h3>

The frequency of the sound heard is determined by applying Doppler effect.

f_o = f_s(\frac{v \pm v_0}{v \pm v_s} )

where;

  • -v₀ is velocity of the observer moving away from the source
  • -vs is the velocity of the source moving towards the observer
  • fs is the source frequency
  • fo is the observed frequency
  • v is speed of sound

f_0 = f_s(\frac{v-v_0}{v- v_s} )

f_0 = 512(\frac{340.3 - 10}{340.3 - 65} )\\\\f_0 = 614.3 \ Hz

Learn more about intensity of sound here: brainly.com/question/17062836

3 0
2 years ago
Please someone do this <br>please ​
monitta

The various contributions involved till the chapati is made is given below.

<h3>What is food?</h3>

The substance that we intake for the body to charge up by giving nutrients is called the food.

Wheat is a staple food. We make chapati from flour obtained from the wheat grains.

The various contributions involved till the chapati is made is given below.

                 Take required amount of atta in a container

                                                     ↓

                    Add water accordingly to form a dough

                                                     ↓

                 Apply oil to make dough smooth for long time

                                                    ↓

        Take small dough, make it a ball shaped and apply dry flour

                                                    ↓

               Roll it using rolling pin on the chapati maker plate

                                                    ↓

      After making it circular or any shape you want, place it on hot tawa

                                                    ↓

                               Bake it on both the sides

                                                   ↓

                                      Chapati is ready

Thus, the flow chart is made.

Learn more about food.

brainly.com/question/16327379

#SPJ1

6 0
2 years ago
Identity the following on the wave shown below:
Marta_Voda [28]

Explanation:

Your wavelength is 0.4

Yout Amplitude is 1

7 0
3 years ago
On level ground a shell is fired with an initial velocity of 49.0 m/s at 70.0 โ above the horizontal and feels no appreciable ai
xenn [34]

Answer:

Horizontal component = 16.8 m/s

Vertical component = 46.0 m/s

Explanation:

If we denote the initial velocity by <em>v</em> and the angle above the horizontal by <em>θ</em>,

the horizontal component of this initial velocity is given by

v_x = v\cos \theta

v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}

The vertical component is given by

v_y = v\sin\theta

v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}

3 0
3 years ago
Which of the following are steps for balancing chemical equations?
AveGali [126]

Answer:

C. Recheck the numbers of each atom on each side of the equation

to make sure the sides are equal.

D. Choose coefficients that will balance the equation

Explanation:

In balancing of chemical equation, the number of atoms on both sides must be equal in adherence to the law of conservation of mass.

Using the method of inspection, the equation is first observed to know the relationship between the combining atoms and the resulting ones.

After observing the reaction, put a coefficient that will balance the equation. Then recheck the number of each atom on both side of the equation. One can repeat the process till the equation is balanced.

5 0
4 years ago
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