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Neko [114]
2 years ago
15

Evaluate each expression. 6! = 3! - 2!= 61/ 3! =

Mathematics
1 answer:
My name is Ann [436]2 years ago
7 0

Answer:

6! = 720

3! - 2! = 4

6! ÷ 3! = 120

Step-by-step explanation:

I used a calculator.  ^v^

You might be interested in
Let R(x)=3x3+2x2+x and S(x)=4x2+1. Find R(x)+S(x).
sasho [114]

The function  R(x) + S(x) exists given by 3x^3+6x^2+x+1.

<h3>What is a function?</h3>

An expression, rule, or law that describes a relationship between one variable (independent variable) and another variable (dependent variable) exists named a function.

Let the functions be R(x)=3x^3+2x^2+x and S(x)=4x^2+1.

Adding both of the equations, we get

$R(x)+S(x)=(3x^3+2x^2+x) +(4x^2+1)

simplifying both of the equations we get

$R(x)+S(x)=3x^3+2x^2+x+4x^2+1

=3x^3+6x^2+x+1

Therefore, the function  R(x) + S(x) exists given by 3x^3+6x^2+x+1.

To learn more about function refer to:

brainly.com/question/12431044

#SPJ9

7 0
1 year ago
IQ scores are known to be normally distributed. The mean IQ score is 100 and the standard deviation is 15. What percent of the p
Masja [62]

Answer:

47.06% of the population has an IQ between 85 and 105.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 15

What percent of the population has an IQ between 85 and 105?

This is the pvalue of Z when X = 105 subtracted by the pvalue of Z when X = 85. So

X = 105

Z = \frac{X - \mu}{\sigma}

Z = \frac{105 - 100}{15}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293.

X = 85

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 100}{15}

Z = -1

Z = -1 has a pvalue of 0.1587

So 0.6293 - 0.1587 = 0.4706 = 47.06% of the population has an IQ between 85 and 105.

5 0
3 years ago
HELP ASAP FOR BRAINLIEST: The time required to finish a test is normally distributed with a mean of 60 minutes and a standard de
adelina 88 [10]

Answer: 0.81859

Step-by-step explanation:

Using the formula ;

Z = \frac{x-u}{standard deviation}

where u = mean

Therefore the probability that a student will finish the test between 40 and 70 will be :

P ( 40≤X≤70 ) = P(X≤70) - P(X≤40)

P ( 60-40/10) , P( 60 - 70 / 10)

=  2 , -1

= P (Z ≤ 2) - P( Z ≤ -1 )

From normal table , we have

0.97725 - 0.15866

Therefore the probability that a student will finish the test between 40 and 70 minutes = 0.81859

8 0
3 years ago
You would like to determine whether eating before bed influences sleep patterns. List each step you would take to conduct a stat
Arte-miy333 [17]

Answer:

get 2 groups

independent and dependent variable

hypothesis

Step-by-step explanation:

4 0
2 years ago
Which of the following equations is not exponential? a)y = 1x b)y = (1/2)x c)y = -2x
Y_Kistochka [10]
I'm not sure but y=1x
3 0
3 years ago
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