A light ray is incident on a reflecting surface. If the light ray makes a 40° angle with respect to the normal to the surface, w
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Answer:
The magnitude of the magnetic field is 7.49x10⁻⁶T
Explanation:
The magnetic field is:
Where
i = current = 3 A
R = radius = 2.4 cm = 0.024 m
r = distance = 0.72 cm = 7.2x10⁻³m
Replacing:
Answer:
Magnetic force,
Explanation:
It is given that,
Velocity of proton,
Angle between velocity and the magnetic field, θ = 53°
Magnetic field, B = 0.49 T
The mass of proton,
The charge on proton,
The magnitude of magnetic force is given by :
So, the magnitude of the magnetic force on the proton is . Hence, this is the required solution.