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rosijanka [135]

3 years ago

12

A light ray is incident on a reflecting surface. If the light ray makes a 40° angle with respect to the normal to the surface, w

hat is the exact angle (in degrees) made by the reflected ray relative to the normal? Do not include units with your answer.

1 answer:

mash [69]3 years ago

7 0

Answer:

40°

Explanation:

when a ray light is incident on a surface it makes a 40° angle with the normal to the surface (reflecting surface ). this called angle of incidence.

And the angle made by reflected ray with the normal to the surface is called angle of reflection.

by the law of reflection angle of incidence is equal to the angle of reflection

hence the answer to the question is 40° ( because ∠i =∠r )

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Answer:

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The kinetic energy of the mass at the instant it passes back through its equilibrium position is about 1.20 J

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall Elastic Potential Energy formula as follows:

$\boxed{E_p = \frac{1}{2}k x^2}$

where:

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<em>x = spring extension ( compression ) ( m )</em>

Let us now tackle the problem!

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<u>Given:</u>

mass of object = m = 1.25 kg

initial extension = x = 0.0275 m

final extension = x' = 0.0735 - 0.0275 = 0.0460 m

<u>Asked:</u>

kinetic energy = Ek = ?

<u>Solution:</u>

<em>Firstly , we will calculate the spring constant by using </em><em>Hooke's Law</em><em> as follows:</em>

$F = k x$

$mg = k x$

$k = mg \div x$

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$\texttt{ }$

<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>

$Ep_1 + Ek_1 = Ep_2 + Ek_2$

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$Ek = \frac{1}{2}k (x')^2 + mgh - \frac{1}{2}k x^2$

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$\boxed {Ek \approx 1.20 \texttt{ J}}$

$\texttt{ }$

<h3>Learn more</h3>

Kinetic Energy : brainly.com/question/692781

Acceleration : brainly.com/question/2283922

The Speed of Car : brainly.com/question/568302
Young Modulus : brainly.com/question/9202964
Simple Harmonic Motion : brainly.com/question/12069840

$\texttt{ }$

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Elasticity

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Answer:

<h2>Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.</h2>

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