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svp [43]
3 years ago
6

C2H5OH( l) + 3O2( g) → 2CO2( g) + 3H2O( l); Δ H = –1.37 × 103 kJ Consider the following propositions: I. The reaction is endothe

rmic II. The reaction is exothermic. III. The enthalpy term would be different if the water formed was gaseous. Which of these propositions is (are) true?
Chemistry
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

II. The reaction is exothermic.

III. The enthalpy term would be different if the water formed was gaseous.

Explanation:

For the reaction:

C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(l)

The  ΔH is -1.37×10³ kJ. As the change in enthalpy is <0,<em> II. The reaction is exothermic.</em>

The ΔH formation of a compound is different if the chemical is in liquid or gaseous phase. For that reason: <em>III. The enthalpy term would be different if the water formed was gaseous.</em>

<em></em>

I hope it helps!

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water’s molar mass is 18.01 g/mol. The molar mass of glycerol is 92.09 g/mol. At 25 celsius, glycerol is more viscous than water
Gemiola [76]

Answer is: glycerol because it is more viscous and has a larger molar mass.

Viscosity depends on intermolecular interactions.

The predominant intermolecular force in water and glycerol is hydrogen bonding.

Hydrogen bond is an electrostatic attraction between two polar groups in which one group has hydrogen atom (H) and another group has highly electronegative atom such as nitrogen (like in this molecule), oxygen (O) or fluorine (F).

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3 years ago
Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to
zhenek [66]

Answer:

<u>D. It will decrease by a factor of 4</u>

Explanation:

According to the question , the equation follows :

A+B\rightarrow C+D

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

Rate\ \alpha [A]^{a}[B]^{b}

r=[A]^{a}[B]^{b}.................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, <u><em>doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,</em></u>

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

r'=[A']^{a}[B']^{b}

Put the value of [A'] , [B'] and r' in the above equation:

2r=[2A]^{a}[B]^{b}...........(2)

Divide equation (1) by (2) we , get

\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}

2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}

Here A and A cancel each other

B and B cancel each other

We get,

2= 2^{a}\times 1^{b}

1^b = 1 ( power of 1 = 1)

2= 2^{a}

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1  = 2

b = 2

Hence the rate law becomes :

r=[A]^{a}[B]^{b}

<u>r=[A]^{1}[B]^{2}.............(3)</u>

Look in the question now, it is asked to calculate the concentration of [B],if  cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

r'=[A]^{1}[B']^{2}

r'=[A]^{1}(\frac{1}{2}[B])^{2}

r'=\frac{1}{4}[A]^{1}[B]^{2}............(a)

But

r=[A]^{a}[B]^{b}..............(b)

Compare equation (a) and (b) , we get

new rate r' =

<u>r' = 1/4 r</u>

7 0
3 years ago
Which substance will have the higher melting point,ethanol or ethane?explain
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Since hydrogen bonding is a stronger intermolecular force than van der Waals forces, more energy is required to separate the molecules of ethanol than the molecules of ethane. Thus ethanol has a higher melting point than ethane.

6 0
3 years ago
What do kinetic and potential energy have in common
adell [148]
Just simply... they both are energy.
Use a bow and arrow as an example:
When you pull back an arrow, potential energy or PE is stored in the string and the limbs of the bow.
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A skeleton equation shows just the reactants and products whereas a balanced equation shows the
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Answer:

<u></u>

  • <em>A skeleton equation shows just the reactants and products whereas a balanced equation shows the</em><u> relative amounts of, or proportion between, reactants and products.</u>

Explanation:

The <em>skeleton equation</em> shows which <em>reactants </em>are being used and which <em>products </em>are being formed.

The reactants are shown on the left and the products are shown on the right side of the equations, separeted by an arrow.

For example, the skeleton equation to obtain water is:

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From it you know that hydrogen and oxygen react to form water, yet you do not know in which ratio they do it.

Then, you balance the equation, adding the appropiate coefficients, to make the number of atoms of each kind on the reactant side equal to the number of the same kind of atoms on the product side.

This is, for the example of water, the number of hydrogen atoms on  the left must equal the number of atoms of hygrogen on the right side, and  the number of oxygen atoms of the left must equal the number of oxygen atoms on the right.

For the water example that is:

  • 2H₂(g) + O₂(g) → 2H₂O (g)

  • Showing that 2 molecuies of hydrogen (or 4 atoms) react with 1 molecule of oxygen (or 2 atoms) to produce 2 molecules of water, and that proportion (relative amounts) will always be true for that reaction.
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