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svp [43]
3 years ago
6

C2H5OH( l) + 3O2( g) → 2CO2( g) + 3H2O( l); Δ H = –1.37 × 103 kJ Consider the following propositions: I. The reaction is endothe

rmic II. The reaction is exothermic. III. The enthalpy term would be different if the water formed was gaseous. Which of these propositions is (are) true?
Chemistry
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

II. The reaction is exothermic.

III. The enthalpy term would be different if the water formed was gaseous.

Explanation:

For the reaction:

C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(l)

The  ΔH is -1.37×10³ kJ. As the change in enthalpy is <0,<em> II. The reaction is exothermic.</em>

The ΔH formation of a compound is different if the chemical is in liquid or gaseous phase. For that reason: <em>III. The enthalpy term would be different if the water formed was gaseous.</em>

<em></em>

I hope it helps!

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The gas phase decomposition of sulfuryl chloride at 600 K SO2Cl2(g)SO2(g) + Cl2(g) is first order in SO2Cl2. During one experime
krok68 [10]

Answer: The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample = 559 min

a = let initial amount of the reactant = 2.83\times 10^{-3}

a - x = amount left after decay process  = 3.06\times 10^{-4}

559min=\frac{2.303}{k}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=\frac{2.303}{559}\log\frac{2.83\times 10^{-3}}{3.06\times 10^{-4}}

k=3.96\times 10^{-3}min^{-1}

The rate constant for the reaction is 3.96\times 10^{-3}min^{-1}

6 0
3 years ago
For the reaction PCl5(g) + heat PCl3(g) + Cl2(g), what will happen when the pressure is increased? There will not be a shift in
Tamiku [17]
When the pressure is increased, the equilibrium will shift to the left to offset the pressure increase. Equilibrium shifting to the left side is favored because the left side has fewer moles of gas than the number of moles of gas on the right-hand side and because it exerts less pressure. Therefore, the answer is there will be a shift toward the reactants. 
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3 years ago
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Lithium hydroxide, LiOH, would react with ________ to form salt and water.
love history [14]

acid

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3 0
3 years ago
2. Barium compounds are chemically very similar to strontium compounds. Water-soluble
harina [27]

The ability of sodium sulfate to act as an antidote to barium chloride poisoning is because displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.

<h3>Why is a solution of sodium sulfate used as an antidote?</h3>

The ability of sodium sulfate to act as an antidote to barium chloride poisoning is because of the reactivity of sodium.

Sodium is a more reactive metal than barium, so it displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.

The equation of the reaction is given below:

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Therefore, the ability of sodium sulfate to act as an antidote to barium chloride poisoning is because displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.

Learn more about about reactivity of metals at: brainly.com/question/24866635

6 0
2 years ago
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An SN2 reaction is a type of ________in which the nucleophile attacks the electrophile _______a leaving group leaves.
mars1129 [50]

Answer:

Nucleophilic reaction

and

Explanation:

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An SN2 reaction is a bimolecular, concerted nucleophilic reaction that leads to inversion of configuration at the carbon center. The leaving group is the group that departs from the frontside of the molecule as the nucleophile attacks from the backside.

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