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4 years ago

How many light sources do you know Pls list them

2 answers:

8 0

The sun is the primary source of light. Other artificial sources are light bulb, torch light and some others. Thats all i can think of.

anastassius [24]4 years ago

6 0

1) Sun.
2) Artifical lamps
3) Torches, bulbs and other household equipments.
4) Street lights
5) Headlights of vehicles.

That's all I could guess. Hope that helped!

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All nuclear energy results in the rapid release of energy, such as in atomic bombs.

Nimfa-mama [501]

<span>It is true that all nuclear energy results in the rapid release of energy, such as in atomic bombs. <span>A process wherein the atom’s nucleus is further divided into two nuclei, that is, fission products, is called nuclear fission. This happens when the nuclei of radioactive elements (e.g. Uranium or Plutonium isotopes) are able to attract neutrons. Because these isotopes’ nuclei are unstable, an addition to their energy causes them to divide into new pieces of neutron. In nuclear reactors, fission occurs when the power plant gathers heat from a steam in a physical process. Nuclear reactors are designed to sustain nuclear chain reactions.</span></span>

3 0

3 years ago

Read 2 more answers

Allen Aby sets up an Atwood Machine and wants to find the acceleration and the tension in the string. Please help him. Two block

Vitek1552 [10]

<u>Answers:</u>

In order to solve this problem we will use Newton’s second Law, which is mathematically expressed after some simplifications as:

This can be read as: The Net Force $F$ of an object is equal to its mass $m$ multiplied by its acceleration $a$ .

We will also need to <u>draw the Free Body Diagram of each block</u> in order to know the direction of the acceleration in this system and find the Tension $T$ of the string (<u>See figure attached). </u>

We already know<u> $m_{2}$ is greater than $m_{1}$ </u>, this means the weight of the block 2 $P_{2}$ is greater than the weight of the block 1 $P_{1}$ ; therefore <u>the acceleration of the system will be in the direction of $P_{2}$ </u>, as shown in the figure attached.

We also know by the information given in the problem that <u>the pulley does not have friction and has negligible mass</u>, and <u>the string is massless</u>.

This means that the tension will be the same along the string regardless of the difference of mass of the blocks.

Now that we have the conditions clear, let’s begin with the calculations:

1) Firstly, we have to find the weight of each block, in order to verify that block 2 is heavier than block 1.

This is done using equation (1), where the force of the weight $P$ is calculated using the <u>acceleration of gravity</u> $g=9.8\frac{m}{s^{2}}$ acting on the blocks:

<u>For block 1: </u>

$P_{1}=m_{1}g$ (3)

$P_{1}=1.5kg(9.8\frac{m}{s^{2}})$

<u>For block 2: </u>

$P_{2}=m_{2}g$ (5)

$P_{2}=2.4kg(9.8\frac{m}{s^{2}})$

Then, we are going to <u>find the acceleration $a$ of the whole system: </u>

$F_{r}=P_{1}+P_{2}$ (7)

Where the Resulting Force $F_{r}$ is equal to the sum of the weights $P_{1}$ and $P_{2}$ .

In the figure attached, note that $P_{1}$ is in opposite direction to the acceleration $a$ , this means it must <u>have a negative sing</u>; while $P_{2}$ is in the same direction of $a$ .

Here we only have to isolate $a$ from equation (8) and substitute the values according to the conditions of the system:

$-14.7N+23.52N=(1.5kg+2.4kg)a$

$8.82N=(3.9kg)a$

Then:

$a=\frac{8.82N }{3.9kg}$

<h2> $a=2.26\frac{m}{ s^{2}}$ </h2><h2>This is the acceleration of the system. </h2>

2) For the second part of the problem, we have to find the tension $T$ of the string.

We can choose either the Free Body Diagram of block A or block B to make the calculations, <u>the result will be the same</u>.

Let’s prove it:

For $m_{1}$

we see in the free body diagram that the <u>acceleration is in the same direction of the tension of the string</u>, so:

$F_{r}=T-P_{1}$ (9)

$T-P_{1}=m_{1}a$ (10)

$T-14.7N=(1.5kg)( 2.26\frac{m}{ s^{2}})$

Then;

<h2> $T=18.09N$ This is the tension of the string </h2><h2> </h2>

For $m_{2}$

we see in the free body diagram that the acceleration is in opposite direction of the tension of the string and must <u>have a negative sign,</u> so:

$F_{r}=T-P_{2}$ (9)

$T-P_{2}=m_{2}a$ (10)

$T-23.52N=(2.4kg)(-2.26\frac{m}{ s^{2}})$

Then;

<h2> $T=18.09N$ This is the same tension of the string </h2>

6 0

3 years ago

A student is bicycling north along Main Street to school. Another student is timing the bicycling student in order to determine

MatroZZZ [7]

The average velocity is -4.17 m/s

Explanation:

The average velocity of a body is given by:

$v=\frac{d}{t}$

where

d is the displacement of the body

t is the time elapsed

For the student in this problem, we have:

Initial position: $x_i = 450 m$

Final position: $x_f = 200 m$

So the displacement is

$d=x_f -x_i = 200 - 450 = -250 m$

The time elapsed is

t = 60 s

Therefore, the average velocity is

$v=\frac{-250}{60}=-4.17 m/s$

Where the negative sign means the student is moving towards the origin.

Learn more about average speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

8 0

4 years ago

Five liters of air at 50 c is warmed to 100c what is the new volume if the pressure remain constant

KonstantinChe [14]

To solve the problem, we can use Charle's law, which states that for an ideal gas at constant pressure the ratio between absolute temperature T and volume V remains constant:
$\frac{T}{V}=k$
For a gas transformation, this law can be rewritten as
$\frac{T_1}{V_1}= \frac{T_2}{V_2}$ (1)
where 1 and 2 label the initial and final conditions of the gas.

Before applying the law, we must convert the temperatures in Kelvin:
$T_1 = 50^{\circ}C + 273 = 323 K$
$T_2 = 100^{\circ}C+273=373 K$
The initial volume of the gas is $V_1 = 5 L$ , so if we re-arrange (1) we find the new volume of the gas:
$V_2 = V_1 \frac{T_2}{T_1}=(5 L) \frac{373 K}{323 K}=5.77 L$

8 0

3 years ago

A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V and t

Zina [86]

Answer:

2000 W

Explanation:

First of all, we need to find the output voltage in the transformer, by using the transformer equation:

$\frac{V_1}{N_1}=\frac{V_2}{N_2}$

where here we have

V1 = 200 V is the voltage in the primary coil

V2 is the voltage in the secondary coil

N1 = 250 is the number of turns in the primary coil

N2 = 500 is the number of turns in the secondary coil

Solving for V2,

$V_2 = N_2 \frac{V_1}{N_1}=(500) \frac{200 V}{250}=400 V$

Now we can find the power output, which is given by

P = VI

where

V = 400 V is the output voltage

I = 5 A is the output current

Substituting,

P = (400 V)(5 A) = 2,000 W

3 0

4 years ago