Answer:
Smallest collector size≈30
Explanation:
Daily sunlight intensity = 1400.
For a collector of 24% efficiency, the absorption per day per
= 0.24*1400 = 336.
For 8 hours, 25days of available sunlight, energy absorbed by collector per metre square , will be = 8* 25 *336 = 67200wh.
This is the amount of sunlight energy which will be trapped by 1. of collector in a month.
To find how many metre square of collector is required to get 2*kwh, we simply divide the required energy by the amount absorbed per square metre.
Smallest size of collected needed =
=29.76
≈30
Answer:
A. Time, t = 4.35s
B. Height of its fall, S = 92.72m
Explanation:
Vo = 0 m/s
Vi = 0.46h m/s
S = h m
a = 9.81 m/s2
To calculate the time taken, we need to get the value of the distance, h.
Using the equations of motion,
Vi^2 = Vo^2 + 2aS
Where Vi = final velocity
Vo = initial velocity
a = acceleration due to gravity
S = height of its fall
(0.46h)^2 = 0 + 2*9.81*h
0.2116h^2 = 19.62h
h = 19.62/0.1648
= 92.722 m
To calculate the time,
S = Vo*t +(1/2)*a*t^2
92.772 = 0 + (1/2)*9.81*t^2
t^2 = 185.44/9.81
= 18.904
t = sqrt(18.904)
= 4.348 s
Answer A: It will rotate to the right
Answer B: it will rotate to the left
Answer C: 17.5 N
Answer D: 2.25 m
Answer:
a)
b)
Explanation:
The complete question is written below:
An emu moving with constant acceleration covers the distance between two points that are 92 m apart in 6.5s. Its speed as it passes the second point is 14 m/s. What are (a) its speed at the first point and (b) its acceleration?
Since we are talking about constant acceleration, we can use the following equations:
(1)
(2)
Where:
is the distance between the two points
is the velocity of the emu at the first point
is the velocity of the emu at the second point
is the time it takes to the emu to cover the distance
is the emu's constant acceleration
Knowing this, let's begin with the answers:
<h2>a) Speed at the first point</h2>
In this situation wi will use equation (1):
(1)
Finding :
(3)
(4)
(5)
<h2>
b) Emu's acceleration</h2>
Now we will substitute (5) in equation (2):
(6)
Finding :
(7) This means the emu is decreasing its speed at a constant rate.