The volume of a gas at 30◦C and 0.13 atm is 61 mL. What volume will the same gas sample occupy at standard conditions?
1 answer:
<span>n= PV/RT </span>
<span>n= 0.44x0.025/0.082x297.5 </span>
<span>n=0.000450913 </span>
<span>22.4L/1 mole = y L/ 0.000450913 </span>
<span>y=0.0101043 L </span>
<span>y = 10.1 mL</span>
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