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Leni [432]
3 years ago
13

The volume of a gas at 30◦C and 0.13 atm is 61 mL. What volume will the same gas sample occupy at standard conditions?

Chemistry
1 answer:
Rainbow [258]3 years ago
8 0
 <span>n= PV/RT </span>
<span>n= 0.44x0.025/0.082x297.5 </span>
<span>n=0.000450913 </span>

<span>22.4L/1 mole = y L/ 0.000450913 </span>
<span>y=0.0101043 L </span>

<span>y = 10.1 mL</span>
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What is the new concentration of 25.0mL added to 125.0mL of 0.150M
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Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

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M₁V₁    =    M₂V₂

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