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Allisa [31]
3 years ago
5

Which components of an atom are found outside of the nucleus

Physics
2 answers:
butalik [34]3 years ago
3 0
Electrons are found outside of the nucleus.
irina [24]3 years ago
3 0

Answer:

electron

Explanation:

I took the test  

You can see other question and answer in my article.  

Just search in search engine with: Learningandassignments diy4pro  

Click on my site and find these related article post:  

Atoms Quiz- Grade 8 Unit 2 Leson 2

Hope it helps.  

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In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.2 m. The mug s
ZanzabumX [31]

Part a can be solve using the equation of trajectory:

Y = x tana + (g*x^2)/ [2(V0^2)*(cos a)^2]

Where y is the height

X is the length

G is the acceleration due to gravity

Vo Is the initail velocity

a is the angle of trajectory

1.2 = 1.35  tan(0) + (9.81*1.35^2)/ [2(V0^2)*(cos 0)^2]

Solve for V0 = 2.729 m/s

b. can be solve using the formula

v = sqrt(2gy)

= sqrt ( 2*1.2*9.81)

= 4.852 m/s  going down ( 0 degree from the horizontal)

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3 years ago
The path the moon's umbra traces across earth's surface is the path of totality.What would you see if you were standing in the p
ivann1987 [24]
You would see the darkest part of the moon
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How do I solve for the maximum speed and height given those accelerations? (please give the formula so I can solve these types o
Sphinxa [80]
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5 0
2 years ago
What is required for equilibrium to exist
creativ13 [48]
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8 0
3 years ago
Calculated the measurement uncertainty for Kinetic Energy when :mass = 1.3[kg] +/- 0.4[kg]velocity= 5.2 [m/s] +/- 0.2 [m/s]KE= 1
andriy [413]

Answer:

\rm KE\pm \Delta KE = 17.6\pm 6.8\ J.

Explanation:

<u>Given:</u>

  • Mass, \rm m\pm\Delta m = 1.3\pm 0.4\ kg.
  • Velocity, \rm v\pm \Delta v = 5.2\pm 0.2\ m/s.

where,

\rm \Delta m,\ \Delta v are the uncertainties in mass and velocity respectively.

The kinetic energy is given by

\rm KE = \dfrac 12 mv^2 = \dfrac 12 \times 1.3\times 5.2^2=17.576\approx 17.6\ J.

The uncertainty in kinetic energy is given as:

\rm \dfrac{\Delta KE}{KE}=\dfrac{\Delta m}{m}+\dfrac{2\Delta v}{v}\\\dfrac{\Delta KE}{17.6}=\dfrac{0.4}{1.3}+\dfrac{2\times 0.2}{5.2}\\\dfrac{\Delta KE}{17.6}=0.384\\\Rightarrow \Delta KE = 17.6\times 0.384 = 6.7854\ J\approx6.8\ J\\\\Thus,\\\\KE\pm \Delta KE = 17.6\pm 6.8\ J.

7 0
3 years ago
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