The distance you free-fall from rest is D = (1/2) (g) (T²) <== memorize this
Height of the platform = (1/2) (9.8 m/s²) (2.4 sec)²
Height = (4.9 m/s²) (5.76 s²)
Height = (4.9/5.76) meters
Height = 28.2 meters (a VERY high platform ... about 93 ft off the water !)
Without air-resistance, your horizontal speed doesn't change. It's constant. Traveling 3.1 m/s for 2.4 sec, you cover (3.1 m/s x 2/4 s) = 7.4 m horizontally.
Answer:
The other angle is 120°.
Explanation:
Given that,
Angle = 60
Speed = 5.0
We need to calculate the range
Using formula of range
...(I)
The range for the other angle is
....(II)
Here, distance and speed are same
On comparing both range
![\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bv%5E2%5Csin%282%5Ctheta%29%7D%7Bg%7D%3D%5Cdfrac%7Bv%5E2%5Csin%282%28%5Calpha-%5Ctheta%29%29%7D%7Bg%7D)
![\sin(2\theta)=\sin(2\times(\alpha-\theta))](https://tex.z-dn.net/?f=%5Csin%282%5Ctheta%29%3D%5Csin%282%5Ctimes%28%5Calpha-%5Ctheta%29%29)
![\sin120=\sin2(\alpha-60)](https://tex.z-dn.net/?f=%5Csin120%3D%5Csin2%28%5Calpha-60%29)
![120=2\alpha-120](https://tex.z-dn.net/?f=120%3D2%5Calpha-120)
![\alpha=\dfrac{120+120}{2}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B120%2B120%7D%7B2%7D)
![\alpha=120^{\circ}](https://tex.z-dn.net/?f=%5Calpha%3D120%5E%7B%5Ccirc%7D)
Hence, The other angle is 120°
The correct answer for this question is "Two-car length rule." While driving, the principle that you should be used to keep the appropriate distance between your vehicle and the vehicle in front of you is to follow the <span>Two-car length rule. This rule is to be followed for safety.</span>
Answer:
Explanation:
It is said to be in equilibrium about the fulcrum . It is the principle of moments.