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natka813 [3]
3 years ago
11

Is it true to say there are forces acting on an object that is traveling at 20 m/s in a

Physics
2 answers:
notsponge [240]3 years ago
7 0

Answer:

<em>Its true</em> i think

Explanation:

natulia [17]3 years ago
7 0
There don’t have to be forced acting on something that is travelling at a constant velocity (Newton’s 1st Law).

If forced are acting they must be balanced forced with Net force = zero.
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vichka [17]
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3 years ago
Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
Evgen [1.6K]

Answer:

Explanation:

In a L C R circuit, the average power is given by

P_{av}=V_{rms}I_{rms}Cos\phi

As given in the question

CosФ = R / Z

And we know that

V_{rms}=I_{rms}\times Z

So

P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}

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6 0
3 years ago
The coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collid
IgorLugansk [536]

Answer:

48.16 %

Explanation:

coefficient of restitution = 0.72

let the incoming speed be = u

let the outgoing speed be = v

kinetic energy = 0.5 x mass x x velocity^{2}

  • incoming kinetic energy = 0.5 x m x x u^{2}

     

  •  coefficient of restitution =\frac{v}{u}

       0.72 =\frac{v}{u}

       v = 0.72u

        therefore the outgoing kinetic energy = 0.5 x m x (0.72u)^{2}

        outgoing kinetic energy = 0.5 x m x 0.5184 x u^{2}

        outgoing kinetic energy = 0.5184 (0.5 x m x x u^{2})

recall that 0.5 x m x x u^{2} is our incoming kinetic energy, therefore

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

5 0
3 years ago
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evablogger [386]
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6 0
3 years ago
True or False
Allisa [31]
False?


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For example:battery operated  cars, are a curiosity and beneficial to the earths environment
4 0
3 years ago
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