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natka813 [3]
3 years ago
11

Is it true to say there are forces acting on an object that is traveling at 20 m/s in a

Physics
2 answers:
notsponge [240]3 years ago
7 0

Answer:

<em>Its true</em> i think

Explanation:

natulia [17]3 years ago
7 0
There don’t have to be forced acting on something that is travelling at a constant velocity (Newton’s 1st Law).

If forced are acting they must be balanced forced with Net force = zero.
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A boat produced water waves of frequency 4 Hz and wavelength 2m, if it reached the shore after 2 seconds how far is the boat fro
kap26 [50]

Answer:

S = 16 m

Explanation:

Given that

The frequency of the water waves, f = 4 Hz

The wavelength of the water waves, λ = 2 m

The time the waves reached the shore, t = 2 s

The relation between the velocity, wavelength, and the frequency of the wave is given by the relation,

                                           v = f λ    m/s

Substituting the given values in the above equation,

                                           v = 4 x 2

                                              = 8 m/s

The velocity of the water waves is v = 8 m/s

The distance between the shore and boat is given by

                                            s = v x t

                                               = 8 x 2

                                               = 16 m

Hence, the distance between the boat and the shore is, s = 16 m

7 0
3 years ago
Name the apparatus used to measure friction force? PLEASE HELP AS SOON AS POSSIBLE
melisa1 [442]
There is no apparatus for it. It is either use something like ruler and table and rub together or rub our hands, and friction force will be showed.
8 0
3 years ago
How do u cure a headache without any pills no bots or I will report u?
Leno4ka [110]

Answer:

Try a Cold Pack. Use a Heating Pad or Hot Compress. Ease Pressure on Your Scalp or Head. Dim the Lights. Try Not to Chew. Hydrate. Get Some Caffeine. Practice Relaxation.

8 0
3 years ago
Read 2 more answers
Which choice displays the effects of quantum mechanics? check all that apply
xxMikexx [17]

Answer:

A,B,C,D,F,G

Explanation:

Edge 2021

8 0
3 years ago
A small 0.13 kg metal ball is tied to a very light (essentially massless) string that is 0.70 m long. The string is attached to
beks73 [17]

Answer:

Explanation:

Let l be th length of pendulum

loss of height

= mg ( l - l cos50)

= mg l ( 1-cos50)

1/2 mv² = mgl ( 1-cos50)

v = √[2gl( 1- cos50)]

= √( 2 x 9.8 x .7 x ( 1-cos50)

= 2.2 m / s

speed at the bottom = 2.2 m /s

b )

centripetal acceleration

= v² / r

= 2.2 x 2.2 / .7

= 6.9 m /s²

C )

If T be the tension

T - mg = mv² / r

T = mg + mv² / r

= .13 X 9.8 + .13 X 6.9

= 2.17 N

7 0
3 years ago
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