Answer:
h = 157.70 meters
Explanation:
Given the following data;
Mass = 5.5 kg
Gravitational potential energy = 8500 Joules
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the height of the object;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Substituting into the formula, we have;
8500 = 5.5*9.8*h
8500 = 53.9h
h = 8500/53.9
h = 157.70 m
The period of the pendulum is 6 seconds.
<h3>What is period?</h3>
Period is the time taken for a simple pendulum to move to(forward) and fro(backward). The s.i unit of period is seconds(s).
Note: When a simple pendulum moves to and fro. it completes one cycle.
From the question, The period of the pendulum is calculated using the formula below.
<h3>Formula</h3>
- T = a+b.............. Equation 1
Where:
- T = Period of the pendulum
- a = Time taken for the pendulum to move forward
- b = Time taken for the pendulum to move backward.
From the question,
Given:
Substitute the values above into equation 1
Hence, The period of the pendulum is 6 seconds.
Learn more about period here: brainly.com/question/21924087
Answer:
The change in the mechanical energy of the projectile is 43,750 J
Explanation:
Given;
mass of the projectile, m = 5 kg
initial velocity of the projectile, u = 200 m/s
final velocity of the projectile, v = 150 m/s
The change in mechanical energy is calculated from the principle of conservation of energy;
ΔP.E = ΔK.E
The change in potential energy is zero (0)
0 = ΔK.E
ΔK.E = K.E₁ - K.E₂
ΔK.E = ¹/₂mu² - ¹/₂mv²
ΔK.E = ¹/₂m(u² - v²)
ΔK.E = ¹/₂ x 5(200² - 150²)
ΔK.E = 43,750 J
Therefore, the change in the mechanical energy of the projectile is 43,750 J
Answer:
The average current is 19.567 A
Solution:
As per the question:
Charge, Q = 
Time, t = 
Now,
We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:
I = 
(1)
Now, the charge that was transferred is 86 % of the original value.
Therefore,
We replace Q by 0.86Q in eqn (1):
I = 
Answer:the answer is D
Explanation:
Plug variables in and calculate
